Java/libGDX - 清理对象创建

正如您在下面看到的，很多代码非常相似。所以我想知道，是否有任何方法来压缩我的按钮的创建，例如通过使用for循环？Java/libGDX - 清理对象创建

private void initButtons() { 
    Rectangle upButtonBounds = new Rectangle(55, 100, 75, 75); 
    Rectangle downButtonBounds = new Rectangle(55, 0, 75, 75); 
    Rectangle leftButtonBounds = new Rectangle(0, 50, 75, 75); 
    Rectangle rightButtonBounds = new Rectangle(105, 50, 75, 75); 
    Rectangle jumpButtonBounds = new Rectangle(VIEWPORT_WIDTH - 185, 115, 80, 80); 
    Rectangle attackButtonBounds = new Rectangle(VIEWPORT_WIDTH - 185, 25, 80, 80); 
    Rectangle magicButtonBounds = new Rectangle(VIEWPORT_WIDTH - 100, 75, 80, 80); 

    upButton = new GameButton(upButtonBounds, "up"); 
    downButton = new GameButton(downButtonBounds, "down"); 
    leftButton = new GameButton(leftButtonBounds, "left"); 
    rightButton = new GameButton(rightButtonBounds, "right"); 
    jumpButton = new GameButton(jumpButtonBounds, "jump"); 
    attackButton = new GameButton(attackButtonBounds, "attack"); 
    magicButton = new GameButton(magicButtonBounds, "magic"); 

    addActor(upButton); 
    addActor(downButton); 
    addActor(leftButton); 
    addActor(rightButton); 
    addActor(jumpButton); 
    addActor(attackButton); 
    addActor(magicButton); 
}

来源

2015-12-08 zark0

你可以做一些数组文本，一个具有界限，另一个名字，然后依次通过数据实例化的按钮和通话addActor。 – pvg

@pvg如何将矩形的边界放入浮点数组中并通过浮点数循环？ – zark0

@pvg没关系我想通了，谢谢你的回应:) – zark0

这里有一个方法

 float[][] bounds = {{1,2,3,4}, {5,5,7,8} }; 
     String[] names = { "foo", "bar"}; 

     for (int i = 0; i < bounds.length; i++) 
     { 
      float[] rect = bounds[i]; 
      addActor(new GameButton(new Rectangle(rect[0], rect[1], rect[2], rect[3]), names[i])); 
     }

来源

2015-12-08 03:45:41 pvg

Java/libGDX - 清理对象创建

回答

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