使用数据透视表排序

Question

SELECT * 
FROM 
    (SELECT 
     datename(month, [date]) as [Month], 
     planttype, 
     (sum(noof50kgsbags * 50))[Total Kgs] 
    FROM 
     K_FP_Indent 
    WHERE 
     (date BETWEEN '2013-04-01 00:00.000' AND getdate()) 
     AND (attrited = 'True') 
    GROUP BY 
     datename(month, [date]), month([date]), planttype,[date]) as s 
PIVOT 
(
    SUM([Total Kgs]) 
    FOR [planttype] IN (A,B,C,D) 
) AS s2 

如何使用order by语句查询此查询？我知道，我们不能为嵌入式查询

输出使用命令：

Month A  B   C  D 
April x  X   X  X 
August X  X   X  X 
July X  X   X  X 

期望中的OP

Month A  B   C  D 
April x  X   X  X 
July X  X   X  X 
August X  X   X  X 

Answer 1

尝试这一个 -

查询：

DECLARE @temp TABLE 
(
     planttype CHAR(1) 
    , [Date] DATETIME 
    , noof50kgsbags FLOAT 
    , attrited VARCHAR(5) 
) 

INSERT INTO @temp (planttype, [Date], noof50kgsbags, attrited) 
VALUES 
    ('a', '20130401', 5, 'True'), 
    ('b', '20130801', 5, 'True'), 
    ('c', '20130701', 7, 'True') 

SELECT s2.[Month], a, b, c, d 
FROM 
(
    SELECT 
      [Month] = DATENAME(MONTH, [Date]) 
     , mt = MONTH([Date]) 
     , planttype 
     , [Total Kgs] = SUM(noof50kgsbags * 50) 
    FROM @temp 
    WHERE [Date] BETWEEN '2013-04-01 00:00.000' AND GETDATE() 
     AND attrited = 'True' 
    GROUP BY 
      DATENAME(MONTH, [Date]) 
     , MONTH([Date]) 
     , planttype 
) s 
PIVOT 
(
    SUM([Total Kgs]) 
    FOR [planttype] IN (a, b, c, D) 
) s2 
ORDER BY mt 

输出：

Month  a  b  c  d 
--------- ------ ------- ------- ------- 
April  250 NULL NULL NULL 
July  NULL NULL 350  NULL 
August NULL 250  NULL NULL 

更新：如何使用以便通过子句嵌入式查询

SELECT * 
FROM 
(
    SELECT TOP (100) PERCENT --<-- 
      [Month] = DATENAME(MONTH, [Date]) 
     , planttype 
     , [Total Kgs] = SUM(noof50kgsbags * 50) 
    FROM @temp 
    WHERE [Date] BETWEEN '2013-04-01 00:00.000' AND GETDATE() 
     AND attrited = 'True' 
    GROUP BY 
      DATENAME(MONTH, [Date]) 
     , MONTH([Date]) 
     , planttype 
    ORDER BY MONTH([Date]) 
) s 
PIVOT 
(
    SUM([Total Kgs]) 
    FOR [planttype] IN (a, b, c, D) 
) s2