Swift JSON解析用户名和密码

我想通过JSON格式将用户名&密码作为NSDictionary发布。我得到这个以下错误：Swift JSON解析用户名和密码

域= NSCocoaErrorDomain代码= 3840“
JSON文字不与数组或对象和选项，允许片段不设置启动。”
的UserInfo = {NSDebugDescription = JSON文字不与数组或对象，并选择允许片段不设置启动。}

我的代码如下：

@IBAction func loginAuthentication(_ sender: UIButton) { 
    let username : NSString = NameTextField.text! as NSString 
    let password : NSString = passwordTextField.text! as NSString 

    let parameters = [ 
     "username": "\(username)", 
     "password": "\(password)" 
    ] 
    print(parameters) 

    let headers = [ 
     "content-type": "application/json", 
     "cache-control": "no-cache", 
     "postman-token": "121b2f04-d2a4-72b7-a93f-98e3383f9fa0" 
    ] 

     if let postData = (try? JSONSerialization.data(withJSONObject: parameters, options: [])) { 

     let request = NSMutableURLRequest(url: URL(string: "http://..")!, 
              cachePolicy: .useProtocolCachePolicy, 
              timeoutInterval: 10.0) 
     request.httpMethod = "POST" 
     request.allHTTPHeaderFields = headers 
     request.httpBody = postData 

     print(request.httpBody) 

     // let session = URLSession.shared 

     let task = URLSession.shared.dataTask(with: request as URLRequest) { 
      (data, response, error) -> Void in 
        if (error != nil) { 
             print("Error message \(error)") 

             } else { 
        DispatchQueue.main.async(execute: { 

             if let json = (try? JSONSerialization.jsonObject(with: data!, options: [])) as? NSDictionary 
             { 
              let success = json["error"] as? Bool 

              print("Error from php\(success)") 

              let message = json["message"] as? String 
               // here you check your success code. 
               if (success == false) 
                 { 
                 print("Result1 \(message)") 
                 self.performSegue(withIdentifier: "", sender: self) 
                 } 
               else 
                 { 
                  self.dismiss(animated: true, completion: nil) 
                  print("Result2 \(message)") 
                 } 

             } 

             }) 
           } 
     } 

     task.resume() 
} 
}

来源

2017-01-16 SwiftUser

http://stackoverflow.com/a/41328809/6656894参考此答案@SwiftUser –

@HimanshuMoradiya我没试过你的脚本，但还是我通过它得到。我感觉Xcode正在发送空包。 – SwiftUser

兄弟给我你的项目，我会检查它。 –

的问题在我看来像你字符串未正确序列化。不要使用当前的json序列化方法，只需将swift字典转换为数据即可。

//Start with a dictionary 
let body = [ 
    "username": "bob", 
    "password": "admin" 
] 
//Serialize it.... you might want to put this in a do try catch block instead 
let jsonBody = try? JSONSerialization.data(withJSONObject: body, options: .prettyPrinted) 
//Add it to the request 
request.httpBody = jsonBody 

//make the request, etc. 
let task = URLSession.shared.dataTask(with: request as URLRequest){ data,response, error in

来源

2017-01-16 22:06:37

Swift JSON解析用户名和密码

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