2016-07-17 53 views
0

我有下面的代码的问题在PHP :(头文件已通过php发送ERROR:|

<?php echo $_GET["u"]; 
$servername = "localhost"; 
$username = "******"; 
$password = "*****?"; 
$dbname = "*****"; 

// Create connection 
$conn = new mysqli($servername, $username, $password, $dbname); 
// Check connection 
if ($conn->connect_error) { 
    die("Connection failed: " . $conn->connect_error); 
} 
$tt=$_GET["u"]; 
$sql = "SELECT url from code WHERE BINARY short="."'$tt'"; 
$result=$conn->query($sql); 
$data=$result->fetch_assoc(); 
$url="Location: ".$data["url"]; 
header($url); /* Redirect browser */ 
exit(); 
?> 

我的问题,在这条线:(

header($url); /* Redirect browser */ 

$ url变量是一个链接从数据库中。一个拿!

+0

@FirstOne抱歉,但我的英语是弱:( –

回答

1

嗯,它不是说谎,你的脚本的顶部有echo $_GET["u"];

在发送标题之前,必须没有任何输出

+0

感谢您的答复,但问题依然存在:(♥ –

+1

亲爱的我FREIND :)问题soved和我删除
' “ –