cypher如何从其他节点的子串创建独特节点

Question

我是Cypher和Neo4j的新手。我有一组标有“线”每一行是一个很长的字符串，如节点： 0067011990999991950051507004+68750+023550FM-12+038299999V0203301N00671220001CN9999999N9+00001+99999999999

有迹象表明我关心大约两子：year和temp

match(l:Line) 
return toInteger(substring(l.line,15,4)) as year, toInteger(substring(l.line,87,5)) as temp 
limit (5) 

为了给：

year temp 

1941 44 

1942 90 

1942 12 

1948 100 

1948 -21 

我需要创建一套标有“年”为今年的每个唯一值的节点，一组不一的标有“温度”为每一个独特的温度读数。我还需要使用关系has_temp将每年的温度读数关联起来。 。（然后打印一年，温度读数和关系型降序排序的年度顺序

任何帮助，将不胜感激

Answer 1

试试这个：

match(l:Line) 
with toInteger(substring(l.line,15,4)) as year, 
toInteger(substring(l.line,87,5)) as temp 
MERGE (y:Year{value:year}) 
MERGE (t:Temp{value:temp}) 
MERGE (y)-[s:has_temp]->(t) 
RETURN year,temp,type(s) as rel_type order by year desc 

如果你想检查后如何导入的节点，你可以这样做：！？

MATCH (y:Year)-[r]->(t:Temp) 
RETURN y.value as year,t.value as temp,type(r) as re_tzpe order by year desc