如何动态更改path_to（）？

Question

目前，我有我要崩溃了为三种方式：

def send_email(contact,email) 

    end 

    def make_call(contact, call) 
    return link_to "Call", new_contact_call_path(:contact => contact, :call => call, :status => 'called') 
    end 

    def make_letter(contact, letter) 
    return link_to "Letter", new_contact_letter_path(:contact => contact, :letter => letter, :status => 'mailed') 
    end 

我想这三个折叠成一个，这样我就可以通过模型的参数之一，它仍然可以正确地创建了path_to。我想通过以下要做到这一点，但坚持：

def do_event(contact, call_or_email_or_letter) 
    model_name = call_or_email_or_letter.class.name.tableize.singularize 
    link_to "#{model_name.camelize}", new_contact_#{model_name}_path(contact, call_or_email_or_letter)" 
    end 

感谢的答案在这里，我曾尝试以下，这让我更接近：

link_to("#{model_name.camelize}", send("new_contact_#{model_name}_path", 
             :contact => contact, 
             :status => "done", 
             :model_name => model_name)) 

但我似乎无法弄清楚如何在＃{model_name}为“：”属性时将它过去，然后将model_name的值发送，而不是字符串，而是引用该对象。

我得到这个工作： - 给点Kadada，因为他在正确的方向:)

def do_event(contact, call_or_email_or_letter) 
    model_name = call_or_email_or_letter.class.name.tableize.singularize 
    link_to("#{model_name.camelize}", send("new_contact_#{model_name}_path", 
              :contact => contact, 
              :status => 'done', 
              :"#{model_name}" => call_or_email_or_letter))          
    end 

Answer 1

让我试试这个：

def do_event(contact, call_or_email_or_letter) 
    model_name = call_or_email_or_letter.class.name.tableize.singularize 
    link_to("#{model_name.camelize}", send("new_contact_#{model_name}_path", 
       contact, call_or_email_or_letter)) 
end