日期帐龄报表+累积式

我目前的工作基于存储在表中最后一个动作日期账龄分析报告，给出如下表所示：日期帐龄报表+累积式

RequestNo UserCode LastActionDate  ActionType 
REQ1  407  12/14/2012 9:47  Saved 
REQ1  407  12/14/2012 9:48  Submitted 
REQ1  407  12/14/2012 9:48  Approved 
REQ1  203  12/17/2012 9:54  Reviewed 
REQ1  242  12/18/2012 10:29 WF Setup in Dev. 
REQ1  203  12/18/2012 15:14 Transport to prod. 
REQ1  242  12/18/2012 15:16 Completed 
REQ2  407  12/27/2012 10:36 Submitted 
REQ2  456  12/27/2012 11:18 Approved 
REQ2  407  12/27/2012 11:27 Approved 
REQ2  203  12/27/2012 17:34 Reviewed 
REQ2  242  12/28/2012 14:07 WF Setup in Dev. 
REQ2  203  12/28/2012 14:11 Transport to prod. 
REQ2  242  12/28/2012 21:27 Completed 
REQ3  407  12/27/2012 11:32 Submitted 
REQ3  456  12/27/2012 11:33 Approved 
REQ3  407  12/27/2012 11:34 Approved 
REQ3  203  12/27/2012 17:33 Reviewed 
REQ3  242  12/27/2012 18:33 WF Setup in Dev. 
REQ3  203  12/28/2012 13:43 Transport to prod. 
REQ3  242  1/3/2013 14:56  Completed

我需要生成具有下列列的老化表 RequestNo，用户代码，ReceivedDate，LastActionDate，操作类型，老龄化（差异LastActionDate和ReceivedDate）Cummulative.Just像见下表

RequestNo UserCode ReceivedDate  LastActionDate  ActionType   Aging Cummulative 
REQ1  407   12/14/2012 9:47  12/14/2012 9:47  Saved    0  0 
REQ1  407   12/14/2012 9:47  12/14/2012 9:48  Submitted   0  0 
REQ1  407   12/14/2012 9:48  12/14/2012 9:48  Approved   0  0 
REQ1  203   12/14/2012 9:48  12/17/2012 9:54  Reviewed   3  3 
REQ1  242   12/17/2012 9:54  12/18/2012 10:29 WF Setup in Dev. 1  4 
REQ1  203   12/18/2012 10:29 12/18/2012 15:14 Transport to prod. 0  4 
REQ1  242   12/18/2012 15:14 12/18/2012 15:16 Completed   0  4 
REQ2  407   12/27/2012 10:36 12/27/2012 10:36 Submitted   0  0 
REQ2  456   12/27/2012 10:36 12/27/2012 11:18 Approved   0  0 
REQ2  407   12/27/2012 11:18 12/27/2012 11:27 Approved   0  0 
REQ2  203   12/27/2012 11:27 12/27/2012 17:34 Reviewed   0  0 
REQ2  242   12/27/2012 17:34 12/28/2012 14:07 WF Setup in Dev. 1  1 
REQ2  203   12/28/2012 14:07 12/28/2012 14:11 Transport to prod. 0  1 
REQ2  242   12/28/2012 14:11 12/28/2012 21:27 Completed   0  1 
REQ3  407   12/27/2012 11:32 12/27/2012 11:32 Submitted   0  0 
REQ3  456   12/27/2012 11:32 12/27/2012 11:33 Approved   0  0 
REQ3  407   12/27/2012 11:33 12/27/2012 11:34 Approved   0  0 
REQ3  203   12/27/2012 11:34 12/27/2012 17:33 Reviewed   0  0 
REQ3  242   12/27/2012 17:33 12/27/2012 18:33 WF Setup in Dev. 0  0 
REQ3  203   12/27/2012 18:33 12/28/2012 13:43 Transport to prod. 1  1 
REQ3  242   12/28/2012 13:43 1/3/2013 14:56  Completed   6  7

来源

2013-08-23 nigel

哪里'ReceivedDate'从何而来？ “Cummulative”是什么意思？如果你指出你正在使用什么样的RDBMS（SQL * flavor *），你也许会想要添加你自己的脚本尝试（即使它们不成功）。 –

什么是RDBMS（SQL Server，MySql，Oracle，.. 。）你使用的是吗？ – peterm

您正在寻找这样的事情？

WITH cte AS 
(
    SELECT * 
    FROM 
    (
    SELECT t.*, ROW_NUMBER() OVER (PARTITION BY RequestNo ORDER BY LastActionDate) rnum 
     FROM Table1 t 
) q 
) 
SELECT c1.RequestNo, c1.usercode, 
     COALESCE(c2.LastActionDate, c1.LastActionDate) ReceivedDate, 
     c1.LastActionDate, c1.ActionType, 
     DATEDIFF(day, COALESCE(c2.LastActionDate, c1.LastActionDate), c1.LastActionDate) Aging 
    FROM cte c1 LEFT JOIN cte c2 
    ON c1.RequestNo = c2.RequestNo 
    AND c1.rnum = c2.rnum + 1 
ORDER BY RequestNo, LastActionDate

输出：

 
| REQUESTNO | USERCODE |     RECEIVEDDATE |     LASTACTIONDATE |   ACTIONTYPE | AGING | 
|-----------|----------|---------------------------------|---------------------------------|--------------------|-------| 
|  REQ1 |  407 | December, 14 2012 09:47:00+0000 | December, 14 2012 09:47:00+0000 |    Saved |  0 | 
|  REQ1 |  407 | December, 14 2012 09:47:00+0000 | December, 14 2012 09:48:00+0000 |   Submitted |  0 | 
|  REQ1 |  407 | December, 14 2012 09:48:00+0000 | December, 14 2012 09:48:00+0000 |   Approved |  0 | 
|  REQ1 |  203 | December, 14 2012 09:48:00+0000 | December, 17 2012 09:54:00+0000 |   Reviewed |  3 | 
|  REQ1 |  242 | December, 17 2012 09:54:00+0000 | December, 18 2012 10:29:00+0000 | WF Setup in Dev. |  1 | 
|  REQ1 |  203 | December, 18 2012 10:29:00+0000 | December, 18 2012 15:14:00+0000 | Transport to prod. |  0 | 
|  REQ1 |  242 | December, 18 2012 15:14:00+0000 | December, 18 2012 15:16:00+0000 |   Completed |  0 | 
|  REQ2 |  407 | December, 27 2012 10:36:00+0000 | December, 27 2012 10:36:00+0000 |   Submitted |  0 | 
|  REQ2 |  456 | December, 27 2012 10:36:00+0000 | December, 27 2012 11:18:00+0000 |   Approved |  0 | 
|  REQ2 |  407 | December, 27 2012 11:18:00+0000 | December, 27 2012 11:27:00+0000 |   Approved |  0 | 
|  REQ2 |  203 | December, 27 2012 11:27:00+0000 | December, 27 2012 17:34:00+0000 |   Reviewed |  0 | 
|  REQ2 |  242 | December, 27 2012 17:34:00+0000 | December, 28 2012 14:07:00+0000 | WF Setup in Dev. |  1 | 
|  REQ2 |  203 | December, 28 2012 14:07:00+0000 | December, 28 2012 14:11:00+0000 | Transport to prod. |  0 | 
|  REQ2 |  242 | December, 28 2012 14:11:00+0000 | December, 28 2012 21:27:00+0000 |   Completed |  0 | 
|  REQ3 |  407 | December, 27 2012 11:32:00+0000 | December, 27 2012 11:32:00+0000 |   Submitted |  0 | 
|  REQ3 |  456 | December, 27 2012 11:32:00+0000 | December, 27 2012 11:33:00+0000 |   Approved |  0 | 
|  REQ3 |  407 | December, 27 2012 11:33:00+0000 | December, 27 2012 11:34:00+0000 |   Approved |  0 | 
|  REQ3 |  203 | December, 27 2012 11:34:00+0000 | December, 27 2012 17:33:00+0000 |   Reviewed |  0 | 
|  REQ3 |  242 | December, 27 2012 17:33:00+0000 | December, 27 2012 18:33:00+0000 | WF Setup in Dev. |  0 | 
|  REQ3 |  203 | December, 27 2012 18:33:00+0000 | December, 28 2012 13:43:00+0000 | Transport to prod. |  1 | 
|  REQ3 |  242 | December, 28 2012 13:43:00+0000 | January, 03 2013 14:56:00+0000 |   Completed |  6 |

这里是SQLFiddle演示

来源

2013-08-23 16:37:41 peterm

是的，它有帮助，但需要计算日期之间的差异，然后处理请求的累积日期。 – nigel

查看更新后的答案。“老化”已添加。你能详细解释'累计'是应该计算的？ – peterm

它将根据requestno计算。例子中REQ1的值将是第一行将是0，那么下一行将是第一行0加上下一行0，第三行总和的前2行加上第3行，直到它到达REQ1的最后一行。 – nigel

日期帐龄报表+累积式

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