1
我有2个表,表-A和表-B,创建和填充如下:SQL更新忽略重复
DROP TABLE IF EXISTS `table_a`;
CREATE TABLE `table_a` (
`a_id` bigint(20) NOT NULL auto_increment,
`user_name` varchar(255) default NULL,
`created_at` datetime default NULL,
`running_count` int default NULL,
PRIMARY KEY (`a_id`)
);
DROP TABLE IF EXISTS `table_b`;
CREATE TABLE `table_b` (
`b_id` bigint(20) NOT NULL auto_increment,
`user_name` varchar(255) default NULL,
`start` datetime default NULL,
`end` datetime default NULL,
`total_count` int default NULL,
PRIMARY KEY (`b_id`)
);
insert into table_a values (NULL, '1', '2013-07-05 01:00:00', 1);
insert into table_a values (NULL, '1', '2013-07-05 02:00:00', 1);
insert into table_a values (NULL, '1', '2013-07-05 02:00:00', 1);
insert into table_a values (NULL, '1', '2013-07-05 03:00:00', 2);
insert into table_a values (NULL, '1', '2013-07-05 07:00:00', 1);
insert into table_a values (NULL, '1', '2013-07-05 08:00:00', 1);
insert into table_b values (NULL, '1', '2013-07-05 00:00:00', '2013-07-05 06:00:00', 0);
insert into table_b values (NULL, '1', '2013-07-05 06:00:01', '2013-07-05 12:00:00', 0);
下面的更新查询表-B与总数:
update table_b b
set
total_count=
(
SELECT IFNULL(SUM(a.running_count),0) total_count
FROM table_a a
where a.created_at BETWEEN b.start and b.end
and a.user_name=b.user_name
and a.created_at between '2013-07-05 00:00:00' and '2013-07-05 23:59:59'
);
结果是好的:
+------+-----------+---------------------+---------------------+-------------+
| b_id | user_name | start | end | total_count |
+------+-----------+---------------------+---------------------+-------------+
| 1 | 1 | 2013-07-05 00:00:00 | 2013-07-05 06:00:00 | 5 |
| 2 | 1 | 2013-07-05 06:00:01 | 2013-07-05 12:00:00 | 2 |
+------+-----------+---------------------+---------------------+-------------+
但我需要的第一个计数是4而不是5,因为有一个重复的re在2013-07-05 02:00:00,应该算作1而不是2。
如何修改更新查询以只计数1如果有多个重复时间戳?
真棒,该诀窍。为了加快速度,我在where子句中添加了一个时间范围,因为table_a可能很大。 – keithc