2016-12-28 49 views
1

我想动态更改WMS层的SLD。我可以通过STYLES参数应用Geoserver保存SLD,但是当我想通过SLD_BODY应用SLD时,它发送请求但没有任何事情发生。我认为一切都很好,但SLD不适​​用于图层。下面是代码:OpenLayers将SLD应用于WMS层3

var SLD = '<?xml version="1.0" encoding="UTF-8"?>'+ 
'<StyledLayerDescriptor version="1.0.0" xmlns="http://www.opengis.net/sld" xmlns:ogc="http://www.opengis.net/ogc"'+ 
    'xmlns:xlink="http://www.w3.org/1999/xlink" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"'+ 
    'xsi:schemaLocation="http://www.opengis.net/sld http://schemas.opengis.net/sld/1.0.0/StyledLayerDescriptor.xsd">'+ 
    '<NamedLayer>'+ 
    '<Name>pmo:'+ layer.Name + '</Name>'+ 
    '<UserStyle>'+ 
     '<Name>pmo:' + layer.Name + '</Name>' + 
     '<Title>A small red flag</Title>'+ 
     '<Abstract>A sample of how to use an SVG based symbolizer</Abstract>'+ 
     '<FeatureTypeStyle>'+ 
     '<Rule>'+ 
      '<Title>Red flag</Title>'+ 
      '<PointSymbolizer>'+ 
      '<Graphic>'+ 
       '<ExternalGraphic>'+ 
       '<OnlineResource xlink:type="simple" xlink:href="burg02.svg" />'+ 
       '<Format>image/svg+xml</Format>'+ 
       '</ExternalGraphic>'+ 
       '<Size>'+ 
       '<ogc:Literal>20</ogc:Literal>'+ 
       '</Size>'+ 
      '</Graphic>'+ 
      '</PointSymbolizer>'+ 
     '</Rule>'+ 
     '</FeatureTypeStyle>'+ 
    '</UserStyle>'+ 
    '</NamedLayer>'+ 
    '</StyledLayerDescriptor>'; 
    SLD = encodeURI(SLD); 

    var source = layer.WMSLayer.getSource(); 
    source.updateParams({ 'STYLES': '' ,'SLD_BODY': SLD }); 

回答

0

而不是你的SLD请更换的这个

var sld='<?xml version="1.0" encoding="UTF-8"?><StyledLayerDescriptor version="1.0.0" xmlns="http://www.opengis.net/sld" xmlns:ogc="http://www.opengis.net/ogc" xmlns:xlink="http://www.w3.org/1999/xlink" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.opengis.net/sld http://schemas.opengis.net/sld/1.0.0/StyledLayerDescriptor.xsd"><NamedLayer><Name></Name><UserStyle><Name></Name><Title>A small red flag</Title><Abstract>A sample of how to use an SVG based symbolizer</Abstract><FeatureTypeStyle><FeatureTypeName>Feature</FeatureTypeName><SemanticTypeIdentifier>generic:geometry</SemanticTypeIdentifier><SemanticTypeIdentifier>simple</SemanticTypeIdentifier><Rule><Title>Red flag</Title><PointSymbolizer><Graphic><ExternalGraphic><OnlineResource xlink:type="simple" xlink:href="https://svn.osgeo.org/qgis/trunk/qgis/images/svg/gpsicons/anchor.svg" /><Format>image/svg+xml</Format></ExternalGraphic><Size><ogc:Literal>20</ogc:Literal></Size></Graphic></PointSymbolizer></Rule></FeatureTypeStyle></UserStyle></NamedLayer></StyledLayerDescriptor>' 
+0

我改变风格来定义,我请求发送到利用Geoserver,我得到这个错误: 了java.lang.RuntimeException: org.xml.sax.SAXParseException; lineNumber 我调试字符串,这是因为我发送的颜色为#字符。我不知道我应该如何纠正它 – danialtehrani

+0

而不是你的sld pls替换上面的代码 – dev9