没有指定MYTBL的类型,
所以我创建了只使用一个简单的解决方案对象列表。
using System;
using System.Linq;
using System.Linq.Expressions;
using System.Collections.Generic;
namespace Test
{
class Program
{
static void Main(string[] args) {
var adresses = FilterByAddress("Address", new List<Person> { new Person { Address = "Address1" }, new Person { Address = "AAAAAA" } });
}
public static IEnumerable<Person> FilterByAddress(string strToCheck, List<Person> list) {
var listParam = Expression.Parameter(typeof(IEnumerable<Person>), "list");
Expression<Func<Person, bool>> contains = a => a.Address.Contains(strToCheck);
var select = typeof(Enumerable).GetMethods().Single(m => m.Name.Equals("Where") && m.GetParameters()[1].ParameterType.GetGenericArguments().Length == 2);
var genericMethod = select.MakeGenericMethod(new[] { typeof(Person) });
var call = Expression.Call(null, genericMethod, new Expression[] { listParam, contains });
var lambda = Expression.Lambda<Func<IEnumerable<Person>, IEnumerable<Person>>>(call, new[] { listParam });
return lambda.Compile().Invoke(list);
}
}
public class Person
{
public string Address { get; set; }
}
}
如果要通过谓词使用过滤器可以传递一个Expresssion<Func<Person, bool>>
作为参数(一行)
static void Main(string[] args) {
var strToCheck = "Address";
var list = new List<Person> { new Person { Address = "Address1" }, new Person { Address = "AAAAAA" } };
var adresses = FilterByAddress(list, p => p.Address.Contains(strToCheck));
}
public static IEnumerable<Person> FilterByAddress(List<Person> list, Expression<Func<Person, bool>> predicateEx) {
var listParam = Expression.Parameter(typeof(IEnumerable<Person>), "list");
var select = typeof(Enumerable).GetMethods().Single(m => m.Name.Equals("Where") && m.GetParameters()[1].ParameterType.GetGenericArguments().Length == 2);
var genericMethod = select.MakeGenericMethod(new[] { typeof(Person) });
var call = Expression.Call(null, genericMethod, new Expression[] { listParam, predicateEx });
var lambda = Expression.Lambda<Func<IEnumerable<Person>, IEnumerable<Person>>>(call, new[] { listParam });
return lambda.Compile().Invoke(list);
}
如果你有一个非常compilicated谓词跨越到多行(一个表达式树可以从一条线拉姆达进行评估),可以使用一个特技构建表达树出谓词的函数功能是这样的:
static void Main(string[] args) {
var strToCheck = "Address";
Func<Person, bool> predicate = p => {
return p.Address.Contains(strToCheck);
};
var list = new List<Person> { new Person { Address = "Address1" }, new Person { Address = "AAAAAA" } };
var adresses = FilterByAddress(list, predicate);
}
public static IEnumerable<Person> FilterByAddress(List<Person> list, Func<Person, bool> predicate) {
var listParam = Expression.Parameter(typeof(IEnumerable<Person>), "list");
Expression<Func<Person, bool>> predicateEx = p => predicate(p);
var select = typeof(Enumerable).GetMethods().Single(m => m.Name.Equals("Where") && m.GetParameters()[1].ParameterType.GetGenericArguments().Length == 2);
var genericMethod = select.MakeGenericMethod(new[] { typeof(Person) });
var call = Expression.Call(null, genericMethod, new Expression[] { listParam, predicateEx });
var lambda = Expression.Lambda<Func<IEnumerable<Person>, IEnumerable<Person>>>(call, new[] { listParam });
return lambda.Compile().Invoke(list);
}
使用通用的方法,通过谓词来筛选列表
static void Main(string[] args) {
var strToCheck = "Address";
Func<Person, bool> predicate = p => {
return p.Address.Contains(strToCheck);
};
var list = new List<Person> { new Person { Address = "Address1" }, new Person { Address = "AAAAAA" } };
var adresses = FilterBy<Person>(list, predicate);
}
public static IEnumerable<T> FilterBy<T>(List<T> list, Func<T, bool> predicate) {
var listParam = Expression.Parameter(typeof(IEnumerable<T>), "list");
Expression<Func<T, bool>> predicateEx = p => predicate(p);
var select = typeof(Enumerable).GetMethods().Single(m => m.Name.Equals("Where") && m.GetParameters()[1].ParameterType.GetGenericArguments().Length == 2);
var genericMethod = select.MakeGenericMethod(new[] { typeof(T) });
var call = Expression.Call(null, genericMethod, new Expression[] { listParam, predicateEx });
var lambda = Expression.Lambda<Func<IEnumerable<T>, IEnumerable<T>>>(call, new[] { listParam });
return lambda.Compile().Invoke(list);
}
}
是什么转换之间的区别' 。选择()'到表达式树和'.Contains()'到表达式树?没有。所以如果你知道如何转换'Select',你应该知道如何转换'Contains'。 –
谢谢。但我对表达树并不陌生,因此没有多少资源。如果你知道答案,请帮我 – Arian
SO包含很多例子,如何编写调用某种方法的表达式树,例如'Any'' Where'等等。你可以查看几个例子:[第一](https://stackoverflow.com/questions/45887790/access-childrenlist-related-property-in-expression-tree)和[second](https://stackoverflow.com/问题/ 45765350 /创建谓上带有一个含binaryexpression- - 多参数)。主要思想是你从相应的'MethodInfo'创建'MethodCallExpression'。顺便说一下,为什么你想将你的例子转换成'ExpressionTree'? –