复制wav文件C++

Question

我的程序（见下文）创建一个带有标题的wav文件等等。我可以打开它，但不会复制所有的数据块。标题正常：我可以用WMP打开文件，我可以听到一些噪音，但对于数据，它实际上并不复制所有文本。我用Wordpad打开了两个wav文件，数据只收集前三行字符，然后是所有空格（所以数据大小很好）。

fstream ifs(FileInputPath->c_str(), ios_base::in); 
cout<< "PATH :" << FileInputPath->c_str()<<endl; 
ofstream outfile("C:/Users/miguel/Desktop/proj/Automatic_Visual_Speech_v0.9_beta/exemplo.wav", ofstream::out); 
if (ifs.is_open() && outfile.is_open()) 
{ 
    char First_Chunk_ID[5]=""; //RIFF 
    ifs.read(First_Chunk_ID,4); 
    outfile.write(First_Chunk_ID,4); 

    long File_Size; // FileSize 
    ifs.read(reinterpret_cast<char*>(&File_Size), sizeof(long)); 
    outfile.write(reinterpret_cast<char*>(&File_Size),sizeof(long)); 

    char Form_Type_ID[5] =""; //Formato 
    ifs.read(Form_Type_ID,4); 
    outfile.write(Form_Type_ID,4); 

    char Second_Chunk_ID[5] = ""; //2ºPedaco 
    ifs.read(Second_Chunk_ID,4); 
    outfile.write(Second_Chunk_ID,4); 

    /*char * charArray_Wave_Format_Size = new char; 
    ifs.read(charArray_Wave_Format_Size, sizeof(long));*/ 

    long Wave_Format_Size; //Tamanho do 2º Pedaço 
    ifs.read(reinterpret_cast<char*>(&Wave_Format_Size), sizeof(long)); 
    outfile.write(reinterpret_cast<char*>(&Wave_Format_Size), sizeof(long)); 

    char Wave_Format_Info[3] = ""; //Tipo de formato! 
    ifs.read(Wave_Format_Info, 2); 
    outfile.write(Wave_Format_Info,2); 

    short NumChannels; //Canais 
    ifs.read(reinterpret_cast<char*>(&NumChannels),2); 
    outfile.write(reinterpret_cast<char*>(&NumChannels),2); 

    long SampleRate; 
    ifs.read(reinterpret_cast<char*>(&SampleRate),4); 
    outfile.write(reinterpret_cast<char*>(&SampleRate),4); 

    long ByteRate; 
    ifs.read(reinterpret_cast<char*>(&ByteRate),4); 
    outfile.write(reinterpret_cast<char*>(&ByteRate),4); 

    short BlockAlign; 
    ifs.read(reinterpret_cast<char*>(&BlockAlign),2); 
    outfile.write(reinterpret_cast<char*>(&BlockAlign),2); 

    short BitsPerSample; 
    ifs.read(reinterpret_cast<char*>(&BitsPerSample),2); 
    outfile.write(reinterpret_cast<char*>(&BitsPerSample),2); 

    char Third_Chunk_ID[5] = ""; 
    ifs.read(Third_Chunk_ID, 4); 
    outfile.write(Third_Chunk_ID,4); 

    long charArray_Data_Size; 
    ifs.read(reinterpret_cast<char*>(&charArray_Data_Size), sizeof(long)); 
    outfile.write(reinterpret_cast<char*>(&charArray_Data_Size),sizeof(long)); 
      char Data[81600]="";// if you want to read 10000 chars, make a buffer of 10000 chars 
    ifs.read(Data,charArray_Data_Size+1); // use read(), not get(). Everything in the file is binary 
    outfile.write(Data,charArray_Data_Size+1); 
    outfile.close(); 
} 

Answer 1

您不显示如何打开输出文件，因此我使用了一种心理猜测：您打开的文件不是二进制文本。

• http://en.cppreference.com/w/cpp/io/ios_base/openmode
• http://en.cppreference.com/w/cpp/io/basic_ofstream/basic_ofstream