如何使用PHP从Google Geocoding API获取街道名称，电话号码，城市，州名？

Question

我想重新格式化地址。

所以我想使用Google地理编码API。 这里是一个输出

{ 
    "results" : [ 
     { 
     "address_components" : [ 
      { 
       "long_name" : "301", 
       "short_name" : "301", 
       "types" : [ "subpremise" ] 
      }, 
      { 
       "long_name" : "880", 
       "short_name" : "880", 
       "types" : [ "street_number" ] 
      }, 
      { 
       "long_name" : "N Street", 
       "short_name" : "N St", 
       "types" : [ "route" ] 
      }, 
      { 
       "long_name" : "South Addition", 
       "short_name" : "South Addition", 
       "types" : [ "neighborhood", "political" ] 
      }, 
      { 
       "long_name" : "Anchorage", 
       "short_name" : "Anchorage", 
       "types" : [ "locality", "political" ] 
      }, 
      { 
       "long_name" : "Anchorage", 
       "short_name" : "Anchorage", 
       "types" : [ "administrative_area_level_2", "political" ] 
      }, 
      { 
       "long_name" : "Alaska", 
       "short_name" : "AK", 
       "types" : [ "administrative_area_level_1", "political" ] 
      }, 
      { 
       "long_name" : "United States", 
       "short_name" : "US", 
       "types" : [ "country", "political" ] 
      }, 
      { 
       "long_name" : "99501", 
       "short_name" : "99501", 
       "types" : [ "postal_code" ] 
      } 
     ], 
     "formatted_address" : "880 N Street #301, Anchorage, AK 99501, USA", 
     "geometry" : { 
      "location" : { 
       "lat" : 61.21391800000001, 
       "lng" : -149.908357 
      }, 
      "location_type" : "ROOFTOP", 
      "viewport" : { 
       "northeast" : { 
        "lat" : 61.21526698029151, 
        "lng" : -149.9070080197085 
       }, 
       "southwest" : { 
        "lat" : 61.2125690197085, 
        "lng" : -149.9097059802915 
       } 
      } 
     }, 
     "partial_match" : true, 
     "types" : [ "subpremise" ] 
     } 
    ], 
    "status" : "OK" 
} 

我如何获得门牌号，街道地址，套房＃（如果有的话），城市，州，邮编。

令我困惑的部分是address_component具有不同的组件。我怎么能说出每个人的立场？

我想我可以做这样的事情让我需要什么

<?php 
$obj = json_decode($json, true); 

$c = $obj['results'][0]['address_components']; 
echo '</pre>'; 
echo 'BUILDING NAME: ' . $c[1]['long_name'] . "<br>\n"; 
echo 'BUILDING NUMBER: ' . $c[2]['long_name'] . "<br>\n"; 
echo 'STREET NAME: ' . $c[3]['long_name'] . "<br>\n"; 
echo 'CITY: ' . $c[5]['long_name'] . "<br>\n"; 
echo 'COUNTY: ' . $c[6]['long_name'] . "<br>\n"; 
echo 'STATE: ' . $c[7]['short_name'] . "<br>\n"; 
echo 'COUNTRY: ' . $c[8]['short_name'] . "<br>\n"; 
echo 'POSTAL CODE: ' . $c[9]['short_name'] . "<br>\n"; 
?> 

但是这不会对所有地址工作。使用上面的地址是我的输出。因为你可以告诉标签不符合数据。

BUILDING NAME: 880 
BUILDING NUMBER: N Street 
STREET NAME: South Addition 
CITY: Anchorage 
COUNTY: Alaska 
STATE: US 
COUNTRY: 99501 

我怎样才能得到理想的结果，每次都是正确的？ 我的假设，我会不知何故必须检查类型值，但我不知道如何以及我需要看什么规则。

Answer 1

这里有一个快速功能我扔在一起，这里有一个fiddle：

function getAddress($elements){ 
    $addr = []; 
    foreach($elements as $e){ 
     if(isset($e['types']) && in_array("street_number",$e['types'])) $addr['street_number'] = $e['long_name']; 
     if(isset($e['types']) && in_array("street_number",$e['types'])) $addr['route'] = $e['long_name']; 
     if(isset($e['types']) && in_array("administrative_area_level_2",$e['types'])) $addr['city'] = $e['long_name']; 
    } 
    return $addr; 
} 

我没有做所有的工作你虽然。这只是给你一个如何去做的例子。你必须编辑它才能获得其余的信息。

使用范例：

$obj = json_decode($json, true); 
$c = $obj['results'][0]['address_components']; 
$address_parts = getAddress($c); 

输出一个简单的数组：

array(3) { ["street_number"]=> string(3) "880" ["route"]=> string(3) "880" ["city"]=> string(9) "Anchorage" }