我最近将PHP版本从4改为5.3。我现在是如何一些代码不工作了。当用户点击链接时,我有一个PHP脚本,可以将表单中的数据提取到新表单中。从PHP版本4切换到版本5.3 - 代码不再工作
首先,它识别用户/帐户之后,它发现表单数据。
这是帐户数据的代码:
$account_info = ft_get_account_info($_SESSION["ft"]["account"]["account_id"]);
$emailadresse = ($account_info['email']);
$accountid = ($account_info['account_id']);
$firstname =($account_info['first_name']);
$lastname =($account_info['last_name']);
.... ....
这工作,以及i可以通过例如显示数据:
<?php echo $_POST['firstname']; ?>
然后我得到这个代码以获取并显示表格数据:
$submission_info = ft_get_submission_info($form_id, $submission_id);
$submission_id = ($submission_info['submission_id']);
$partname = ($submission_info['partname']);
$ponumber = ($submission_info['ponumber']);
....
....
<?php echo $_POST['partname']; ?>
这不是在PHP 5.3版本的工作了。
谁能告诉我需要重新写这个代码到,为了它的工作... ????
在此先感谢!
除了我对这个ft_get_account_info代码中的注释:
$_SESSION["ft"]["account"] = ft_get_account_info($account_info["account_id"]);
这对于ft_get_submission_info:在错误报告
/**
* Returns all information about a submission. N.B. Would have been nice to have made this just a
* wrapper for ft_get_submission_info, but that function contains hooks. Need to revise all core
* code to allow external calls to optionally avoid any hook calls.
*
* @param integer $form_id
* @param integer $submission_id
*/
function ft_api_get_submission($form_id, $submission_id)
{
global $g_table_prefix, $g_api_debug;
// confirm the form is valid
if (!ft_check_form_exists($form_id))
{
if ($g_api_debug)
{
$page_vars = array("message_type" => "error", "error_code" => 405, "error_type" => "user");
ft_display_page("../../global/smarty/messages.tpl", $page_vars);
exit;
}
else
return array(false, 405);
}
if (!is_numeric($submission_id))
{
if ($g_api_debug)
{
$page_vars = array("message_type" => "error", "error_code" => 406, "error_type" => "user");
ft_display_page("../../global/smarty/messages.tpl", $page_vars);
exit;
}
else
return array(false, 406);
}
// get the form submission info
$submission_info = mysql_query("
SELECT *
FROM {$g_table_prefix}form_{$form_id}
WHERE submission_id = $submission_id
");
$submission = mysql_fetch_assoc($submission_info);
return $submission;
}
没有。
什么是“ft_get_submission_info”功能吗?一切看起来都是完全可以接受的代码 – cernunnos
您的错误日志是否包含任何有价值的信息?也许任何被弃用的功能或类似的东西? – DKSan
您是否打开了错误报告? – Mark