初级 - 使用XML XML转换XSLT

Question

我有其由从MySQL收集数据的PHP文件馈送的视频播放器，并且将其输出作为XML如下：

当前PHP/XML输出

 <?xml version="1.0" ?> 
<CONTENT> 
    <GALLERY name="John" vid="1" vidtitle="NL - 22nd Jan 2011 - FO" sport="Soccer" /> 
    <GALLERY name="John" vid="2" vidtitle="NL - 22nd Jan 2011 - DL" sport="Golf" /> 
    <GALLERY name="sportshound" vid="28" vidtitle="Tiger Woods" sport="Golf" /> 
    <GALLERY name="sportshound" vid="29" vidtitle="Tigerwoodstest" sport="Golf" /> 
    <GALLERY name="John" vid="36" vidtitle="5 iron behind April" sport="Golf" /> 
    <GALLERY name="John" vid="35" vidtitle="face on april" sport="Golf" /> 
    <GALLERY name="John" vid="34" vidtitle="wqetfgtgdijuserf" sport="Golf" /> 
    <GALLERY name="John" vid="37" vidtitle="April - 3 iron Behind" sport="Golf" /> 
    <GALLERY name="John" vid="38" vidtitle="April - 7 iron behind" sport="Golf" /> 
    <GALLERY name="John" vid="39" vidtitle="April - 3 wood behind" sport="Golf" /> 
    <GALLERY name="John" vid="40" vidtitle="24 April - 7 iron behind" sport="Golf" /> 
    <GALLERY name="John" vid="41" vidtitle="April 29 Iron behind swing left" sport="Golf" /> 
    <GALLERY name="John" vid="42" vidtitle="29 April iron behind shallowing" sport="Golf" /> 
    <GALLERY name="John" vid="43" vidtitle="1st May Driver Behind" sport="Golf" /> 
    <GALLERY name="John" vid="44" vidtitle="21st May - 6I behind - swing left" sport="Golf" /> 
    <GALLERY name="John" vid="45" vidtitle="Adam Scott - Masters '11 - iron behind" sport="Golf" /> 
    <GALLERY name="John" vid="46" vidtitle="19th June 2011 - Face on - impact" sport="Golf" /> 
    <GALLERY name="John" vid="47" vidtitle="19 June - Behind - 6i" sport="Golf" /> 
    <GALLERY name="John" vid="48" vidtitle="19 June 2011 - Face on - 8i (impact)" sport="Golf" /> 
    <GALLERY name="John" vid="49" vidtitle="19 June 2011 - Face On - 5i (impact)" sport="Golf" /> 
    </CONTENT> 

我一直在寻找几个星期的方式来使用XSLT来转换结构，以便输出由Gallery构建，然后是运动。任何帮助，将不胜感激！

拟议结构

<CONTENT> 
    <GALLERY name="John"> 
    <CATEGORY sport="Soccer"> 
     <ITEM> 
     <vid>1</vid> 
     </ITEM> 
    </CATEGORY> 
    <CATEGORY sport="Golf"> 
     <ITEM> 
     <vid>2</vid> 
     <vid>36</vid> 
     ..... 
     </ITEM> 
    </CATEGORY> 
    <GALLERY/> 
    <GALLERY name="sportshound"> 
    <CATEGORY sport="Golf"> 
     <ITEM> 
     <vid>28</vid> 
     <vid>29</vid> 
     </ITEM> 
    </CATEGORY> 
    <GALLERY/> 
</CONTENT> 

Answer 1

下面是一个简单的样式表：

<xsl:stylesheet 
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
    version="1.0"> 

    <xsl:output indent="yes"/> 

    <xsl:key name="k1" match="GALLERY" use="@name"/> 
    <xsl:key name="k2" match="GALLERY" use="concat(@name, '|', @sport)"/> 

    <xsl:template match="CONTENT"> 
    <xsl:copy> 
     <xsl:apply-templates select="GALLERY[generate-id() = generate-id(key('k1', @name)[1])]"/> 
    </xsl:copy> 
    </xsl:template> 

    <xsl:template match="GALLERY"> 
    <GALLERY name="{@name}"> 
     <xsl:apply-templates select="key('k1', @name)[generate-id() = generate-id(key('k2', concat(@name, '|', @sport))[1])]" mode="sport"/> 
    </GALLERY> 
    </xsl:template> 

    <xsl:template match="GALLERY" mode="sport"> 
    <CATEGORY sport="{@sport}"> 
     <ITEM> 
     <xsl:apply-templates select="key('k2', concat(@name, '|', @sport))/@vid"/> 
     </ITEM> 
    </CATEGORY> 
    </xsl:template> 

    <xsl:template match="GALLERY/@vid"> 
    <vid> 
     <xsl:value-of select="."/> 
    </vid> 
    </xsl:template> 

</xsl:stylesheet> 

想了解更多关于所谓Muenchian分组的访问http://www.jenitennison.com/xslt/grouping/muenchian.xml是XSLT 1.0的做法。

Answer 2

以下是基于新分组功能的XSLT 2.0解决方案。

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"> 

    <xsl:output method="xml" indent="yes"/> 

    <xsl:template match="CONTENT"> 
     <CONTENT> 
      <xsl:for-each-group select="GALLERY" 
       group-by="@name"> 
       <GALLERY name="{current-grouping-key()}"> 
        <xsl:for-each-group select="current-group()" 
         group-by="@sport"> 
         <CATEGORY sport="{current-grouping-key()}"> 
          <ITEM> 
           <xsl:apply-templates select="current-group()"/> 
          </ITEM> 
         </CATEGORY> 
        </xsl:for-each-group> 
       </GALLERY>   
      </xsl:for-each-group> 
     </CONTENT> 
    </xsl:template> 

    <xsl:template match="GALLERY"> 
     <vid><xsl:value-of select="@vid"/></vid> 
    </xsl:template> 

</xsl:stylesheet> 

所产生的输出是：

<CONTENT> 
    <GALLERY name="John"> 
     <CATEGORY sport="Soccer"> 
     <ITEM> 
      <vid>1</vid> 
     </ITEM> 
     </CATEGORY> 
     <CATEGORY sport="Golf"> 
     <ITEM> 
      <vid>2</vid> 
      <vid>36</vid> 
      <vid>35</vid> 
      <vid>34</vid> 
      <vid>37</vid> 
      <vid>38</vid> 
      <vid>39</vid> 
      <vid>40</vid> 
      <vid>41</vid> 
      <vid>42</vid> 
      <vid>43</vid> 
      <vid>44</vid> 
      <vid>45</vid> 
      <vid>46</vid> 
      <vid>47</vid> 
      <vid>48</vid> 
      <vid>49</vid> 
     </ITEM> 
     </CATEGORY> 
    </GALLERY> 
    <GALLERY name="sportshound"> 
     <CATEGORY sport="Golf"> 
     <ITEM> 
      <vid>28</vid> 
      <vid>29</vid> 
     </ITEM> 
     </CATEGORY> 
    </GALLERY> 
</CONTENT>