重新安排基于另一个集合集合列表

Question

我有以下查询

neo4j-sh (?)$ 
$start n=node(*) match p=n-[r:LIKES]->items return n,collect(r.w),collect(items.name); 
==> +------------------------------------------------------------------------------------------------------------------+ 
==> | n     | collect(r.w)   | collect(items.name) | 
==> +------------------------------------------------------------------------------------------------------------------+ 
==> | Node[249]{name:"u1"} | [0,0.93]    | ["f5","f2"]   | 
==> | Node[248]{name:"u2"} | [0,-0.76,1,-0.66]  | ["f4","f3","f2","f1"] | 
==> +------------------------------------------------------------------------------------------------------------------+ 

我想重新排序的项目按照类似下面的

==> +------------------------------------------------------------------------------------------------------------------+ 
==> | n     | collect(r.w)   | collect(items.name) | 
==> +------------------------------------------------------------------------------------------------------------------+ 
==> | Node[249]{name:"u1"} | [0.93,0]    | ["f2","f5"]   | 
==> | Node[248]{name:"u2"} | [1,0,-0.66,-0.76] | ["f2","f4","f1","f3"] | 
==> +------------------------------------------------------------------------------------------------------------------+ 

如何RW的排序值我可以根据collect（rw）的排序值重新排列collect（items.name）的元素吗？

Answer 1

我觉得可能是这样

START n=node(*) 
MATCH p=n-[r:LIKES]->items 
WITH n,r,items 
ORDER BY r.w DESC, items.name DESC 
RETURN n,collect(r.w),collect(items.name); 

Answer 2

通过WITH管理您的结果，然后订购它们。然后通过RETURN正常进行聚合。

START n=node(*) 
MATCH p=n-[r:LIKES]->items 
WITH n,r,items 
ORDER BY r.w DESC 
RETURN n,collect(r.w),collect(items.name);