用守护进程作为后台任务启动play2应用程序

Question

我一直在为我的play2应用程序编写启动脚本，但无法让它作为后台任务工作。我开始在docs，并提出了下面的脚本。

脚本：

#! /bin/sh 

# description: Starts autocomplete play app using daemon 
# 1. Go to $APPLICATION_PATH and prepare for dev by doing: play clean compile stage 
# This will create a start script at target/start 
# 2. Start the application by running this script 

. /etc/rc.d/init.d/functions 

PLAY_HOME=/opt/play 
PLAY=$PLAY_HOME/play 
NAME=autocomplete 
DESC="autocomplete application" 
PID_FILE=/var/run/autocomplete/$NAME.pid  

# Path to the JVM 
JAVA_HOME=/usr/java/latest 
export JAVA_HOME 
export PATH=$PATH:$JAVA_HOME/bin 

APPLICATION_PATH=/opt/playapps/autocomplete 

DAEMON_OPTS="-Dconfig.file=/opt/playapps/autocomplete/conf/application-dev.conf" 

start() 
{ 
    echo -n "Starting $DESC with: --pidfile $PID_FILE ${APPLICATION_PATH}/target/start $DAEMON_OPTS" 
    daemon --pidfile $PID_FILE "${APPLICATION_PATH}/target/start $DAEMON_OPTS" 
} 
stop() 
{ 
    echo -n $"Stopping $DESC:" 
    #NOT DONE YET 
} 


case "$1" in 
    start) 
    start 
    ;; 
    stop) 
    stop 
    ;; 
esac 

exit $RETVAL 

我有谷歌这个问题，并找到解决方案，如this，但他们使用的是 启动 - 停止 - 守护，我不会对我的红帽企业Linux服务器发行版5.6（Tikanga） dist。如果可能的话，我宁愿不安装任何其他软件来完成此项工作。我错过了什么让这项工作作为后台任务并将其从控制台中分离出来？ CTRL + D不起作用，CTRL + C退出该过程。

Answer 1

确定这里是favoretti提示后一种解决方案：

#! /bin/sh 

# description: Starts autocomplete play app using daemon 
# 1. Go to $APPLICATION_PATH and prepare for dev by doing: play clean compile stage 
# This will create a start script at target/start 
# 2. Start the application by running this script 
# created by: Jakob 

. /etc/rc.d/init.d/functions 

PLAY_HOME=/opt/play 
PLAY=$PLAY_HOME/play 
NAME=autocomplete 
DESC="autocomplete application" 

# Path to the JVM 
JAVA_HOME=/usr/java/latest 
export JAVA_HOME 
export PATH=$PATH:$JAVA_HOME/bin 

APPLICATION_PATH=/opt/playapps/autocomplete 

DAEMON_OPTS="-Dconfig.file=/opt/playapps/autocomplete/conf/application-dev.conf" 

start() 
{ 
     echo -n "Starting $DESC with: $APPLICATION_PATH/target/start $DAEMON_OPTS &" 
     $APPLICATION_PATH/target/start $DAEMON_OPTS & 
} 
stop() 
{ 
     echo -n $"Stopping $DESC:" 
     kill `cat $APPLICATION_PATH/RUNNING_PID` 
} 


case "$1" in 
    start) 
    start 
    ;; 
    stop) 
     stop 
     ;; 
esac 

exit $RETVAL 

您需要CTRL + d走出这不正是我心目中的控制台。也许有人在那里有更好的解决方案？

Answer 2

这是我的版本，可以在Amazon AMI Linux下自动启动Play 2.2应用程序。在CentOS和RedHat下也一样。其他linux的风格可能需要一点适应。该脚本在单独的用户下启动播放应用程序。

#!/bin/bash 
# description: MyWorkCalendar Play App 
# processname: myworkcalendar 
# chkconfig: 234 20 80 

# User running the Play process 
USER=mywork 
USER_HOME=/home/mywork 

# Java home, add java and play to path 
export JAVA_HOME=$USER_HOME/java_home 
export PATH=$JAVA_HOME/bin:$USER_HOME/play_home:$PATH 

# Path to the application 
APP_PATH=$USER_HOME/app/work-calendar/target/universal/stage 
APP_OPTS="-Dconfig.file=$APP_PATH/conf/application-prod.conf" 

RETVAL=0 

case "$1" in 
    start) 
    echo -n "Starting Play service" 
    rm -f ${APP_PATH}/RUNNING_PID 
    su $USER -c "$APP_PATH/bin/myworkcalendar $APP_OPTS >/dev/null" & 
    RETVAL=$? 
    ;; 
    stop) 
    echo -n "Shutting down Play service" 
    kill `cat $APP_PATH/RUNNING_PID` 
    RETVAL=$? 
    ;; 
esac 
exit $RETVAL 

把脚本到/etc/init.d，使其可执行与chkconfig的注册它：

sudo chmod 755 script-name 
sudo chkconfig --add script-name 
sudo chkconfig script-name on 

Answer 3

这里是我的版本的开始/播放为2.2停止脚本：

http://vladsprogrammingblog.blogspot.com/2014/01/play-startstop-script.html