2
有人可以为我跑这个,告诉我需要多长时间吗?我的笔记本电脑采用了60年代。我无法分辨这是我的笔记本电脑是蹩脚的还是我的代码。可能都是。 我刚开始学习MatLab,所以我还不熟悉哪些功能比其他功能更适合特定任务。如果您对如何改进此代码有任何建议,将不胜感激。MatLab代码速度和优化。如何提高?
function gbp
clear; clc;
zi = 0; % initial position
zf = 100; % final position
Ei = 1; % initial electric field
c = 3*10^8; % speed of light
epsilon = 8.86*10^-12; % permittivity of free space
lambda = 1064*10^-9; % wavelength
k = 2*pi/lambda; % wave number
wi = 1.78*10^-3; % initial waist width (minimum spot size)
zr = (pi*wi^2)/lambda; % Rayleigh range
Ri = zi + zr^2/zi; % initial radius of curvature
qi = 1/(1/Ri-1i*lambda/(pi*wi^2)); % initial complex beam parameter
Psii = atan(real(qi)/imag(qi)); % Gouy phase
mat = [1 zf; 0 1]; % transformation matrix
A = mat(1,1); B = mat(1,2); C = mat(2,1); D = mat(2,2);
qf = (A*qi + B)/(C*qi + D); % final complex beam parameter
wf = sqrt(-lambda/pi*(1/imag(1/qf))); % final spot size
Rf = 1/real(1/qf); % final radius of curvature
Psif = atan(real(qf)/imag(qf)); % final Gouy phase
% Hermite - Gaussian modes function
u = @(z, x, n, w, R, Psi) (2/pi)^(1/4)*sqrt(exp(1i*(2*n+1)*Psi)/(2^n*factorial(n)*w))*...
hermiteH(n,sqrt(2)*x/w).*exp(-x.^2*(1/w^2+1i*k/(2*R))-1i*k*z);
% Complex amplitude coefficients function
a = @(n) exp(1i*k*zi)*integral(@(x) Ei.*conj(u(zi, x, n, wi, Ri, Psii)),-2*wi,2*wi);
%----------------------------------------------------------------------------
xlisti = -0.1:1/10000:0.1; % initial x-axis range
xlistf = -0.1:1/10000:0.1; % final x-axis range
nlist = 0:2:20; % modes range
function Eiplot
Efieldi = zeros(size(xlisti));
for nr = nlist
Efieldi = Efieldi + a(nr).*u(zi, xlisti, nr, wi, Ri, Psii)*exp(-1i*k*zi);
end
Ii = 1/2*c*epsilon*arrayfun(@(x)x.*conj(x),Efieldi);
end
function Efplot
Efieldf = zeros(size(xlistf));
for nr = nlist
Efieldf = Efieldf + a(nr).*u(zf, xlistf, nr, wf, Rf, Psif)*exp(-1i*k*zf);
end
If = 1/2*c*epsilon*arrayfun(@(x)x.*conj(x),Efieldf);
end
Eiplot
Efplot
plot(xlisti,real(Ii),xlistf,real(If))
xlabel('x(m)') % x-axis label
ylabel('I(W/m^2)') % y-axis label
end
23.91秒在这里..也许蹩脚的太多,但少蹩脚的可能:0 .... – hyprfrcb
,如果这是你送我的信用卡数据库中的数据我不知道,所以我应该知道在未来这些请求大声笑... – hyprfrcb
哈哈,有趣和非常有效的一点! XD – Raksha