在PHP中创建这个JSON输出？

如何使用PHP创建此JSON输出？在PHP中创建这个JSON输出？

{ 
    "external_ref": "12345", 
    "sale_datetime": "2016-03-01 22:09:00", 
    "customer_name": "Foo Bar", 
    "shipping_address_1": "123 Test Street", 
    "shipping_address_2": "", 
    "shipping_address_3": "City", 
    "shipping_address_4": "County", 
    "shipping_postcode": "AB12 3AB", 
    "shipping_country": "England", 
    "shipping_country_code": "GB", 
    "shipping_method": "STANDARD", 
    "phone": "", 
    "items": [ 
    { 
     "external_ref": "12345", 
     "style": "mens", 
     "size": "Medium", 
     "color": "White", 
     "print_location": "front", 
     "print_x_offset": "0", 
     "print_y_offset": "0", 
     "quantity": 1, 
     "external_url": "url.png", 
     "external_thumbnail_url": "url.jpg" 
    } 
    ] 
}

我这个尝试我自己（见下文），但它未能提交给我送它到API：

//Initiate cURL. 
$ch = curl_init($url); 

$item = array(
    array(
    "external_ref" => 12345, 
    "style" => "mens", 
    "size" => "Medium", 
    "color" => "White", 
    "print_location" => "FRONT", 
    "print_x_offset" => "0", 
    "print_y_offset" => "0", 
    "quantity" => 1, 
    "external_url" => "url.png", 
    "external_thumbnail_url" => "url.jpg" 
) 
); 

//The JSON data. 
$jsonData = array(
    "external_ref"=> 12345, 
    "sale_datetime" => "2016-03-01 22:09:00", 
    "customer_name" => "Foo Bar", 
    "shipping_address_1" => "123 Test Street", 
    "shipping_address_2" => "", 
    "shipping_address_3" => "City", 
    "shipping_address_4" => "County", 
    "shipping_postcode" => "AB12 3AB", 
    "shipping_country" => 'England', 
    "shipping_country_code" => "GB", 
    "shipping_method" => "STANDARD", 
    "phone" => "", 
    "items" => $item 
); 

//Encode the array into JSON. 
$jsonDataEncoded = json_encode($jsonData); 

//Tell cURL that we want to send a POST request. 
curl_setopt($ch, CURLOPT_POST, 1); 

//Attach our encoded JSON string to the POST fields. 
curl_setopt($ch, CURLOPT_POSTFIELDS, $jsonDataEncoded); 

//Set the content type to application/json 
curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type: application/json')); 

//Execute the request 
$result = curl_exec($ch);

我失去了一些重要的东西在这里？这个问题顶部的JSON代码的第一位确实提交了。当我尝试用这个PHP复制这个JSON时，它不会提交。

来源

2016-03-03 Liam McArthur

什么是JSON您要提交什么样子？ – Sammitch

console.log（$ jsonDataEncoded）并将其与您想要的输出进行比较。 –

https://3v4l.org/ugIje确认这与您发布的json完全相同。顺便问一句，你得到的错误是什么？ – IROEGBU

我运行代码，并获得：在sale_datetime格式

{ 
    "external_ref": 12345, 
    "sale_datetime": "2016-03-01 22:09:00", 
    "customer_name": "Foo Bar", 
    "shipping_address_1": "123 Test Street", 
    "shipping_address_2": "", 
    "shipping_address_3": "City", 
    "shipping_address_4": "County", 
    "shipping_postcode": "AB12 3AB", 
    "shipping_country": "England", 
    "shipping_country_code": "GB", 
    "shipping_method": "STANDARD", 
    "phone": "", 
    "items": [ 
    { 
     "external_ref": 12345, 
     "style": "mens", 
     "size": "Medium", 
     "color": "White", 
     "print_location": "FRONT", 
     "print_x_offset": "0", 
     "print_y_offset": "0", 
     "quantity": 1, 
     "external_url": "url.png", 
     "external_thumbnail_url": "url.jpg" 
    } 
    ] 
}

区别：

2016年3月1日22时09分00秒 - 你想要的格式
2016年3月1日22 ：09：00 - 这个fromat中的php输出

and external_ref变成整数不是字符串

来源

2016-03-03 18:03:25

即使在“项目”子阵“print_location”大小写不同 –

是的，你是对的:)，但是笔者明确地说“print_location” =>“FRONT”在他的代码 –

我做了所有的情况下，如“前”与正确他们的代码现在，但我仍然得到相同的错误。 “您正在查找的资源是否已被删除，名称已更改，或者暂时不可用”一个通用的PHP/cURL错误？我从来没有见过它，他们也没有。 –

原来我的URL请求被提交给缺少一个“？”在那里我添加了'token ='。哎呀！

来源

2016-03-04 08:05:33

在PHP中创建这个JSON输出？

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