从firebase存储快速删除图像

Question

我有一个功能，通过滑动tableView单元格从我的firebase数据库中删除一个对象，但我的tableView单元格还包含保存在firebase存储中的图像，我希望图像被删除从数据库中删除数据时，也从存储中读取数据，我该如何实现？

代码删除：

func tableView(_ tableView: UITableView, commit editingStyle: UITableViewCellEditingStyle, forRowAt indexPath: IndexPath) { 
    if editingStyle == .delete { 

     let name = food[indexPath.row].name 
     let ref = Database.database().reference().child("Recipes") 

     ref.queryOrdered(byChild: "Name").queryEqual(toValue: name).observe(.childAdded, with: { (snapshot) in 
      //Removes deleted cell from firebase 
      snapshot.ref.removeValue(completionBlock: { (error, reference) in 
       if error != nil { 
        print("There has been an error: \(error)") 
       } 
       //Removes deleted cell from array 
       food.remove(at: indexPath.row) 
       //Removes deleted cell from tableView 
       tableView.deleteRows(at: [indexPath], with: .left) 
      }) 
     }) 
    } 
} 

代码加载：

let parentRef = Database.database().reference().child("Recipes") 
    let storage = Storage.storage() 

    parentRef.observe(.value, with: { snapshot in 

     if (snapshot.value is NSNull) { 

      // DATA WAS NOT FOUND 
      print("– – – Data was not found – – –") 

     } else { 

      //Clears array so that it does not load duplicates 
      food = [] 

      // DATA WAS FOUND 
      for user_child in (snapshot.children) { 

       let user_snap = user_child as! DataSnapshot 
       let dict = user_snap.value as! [String: String?] 

       //Defines variables for labels 
       let recipeName = dict["Name"] as? String 
       let recipeDescription = dict["Description"] as? String 
       let downloadURL = dict["Image"] as? String 

       let storageRef = storage.reference(forURL: downloadURL!) 

       storageRef.getData(maxSize: 1 * 1024 * 1024) { (data, error) -> Void in 

        let recipeImage = UIImage(data: data!) 

        food.append(Element(name: recipeName!, description: recipeDescription!, image: recipeImage!)) 
        self.tableView.reloadData() 
       } 
      } 
     } 
    }) 

也会很感激，如果有人也能帮助我解决这个其他的问题，我问这个相同的应用程序：Convert observe .value to .childAdded in swift

编辑：

加载从火力的对象时，我已经加入的URL数组：

food.append(Element(name: recipeName!, description: recipeDescription!, image: recipeImage!, downloadURL: downloadURL!)) 

而这正是我试图用它来删除：

let storage = Storage.storage() 
let storageRef = storage.reference() 
let desertRef = storageRef.child(food[indexPath.row].downloadURL) 

//Removes image from storage 
desertRef.delete { error in 
    if let error = error { 
     print(error) 
    } else { 
     // File deleted successfully 
    } 
} 

我不认为这是然而，寻找图像...我得到这个错误：

错误域= FIRStorageErrorDomain代码= -13010“对象的https：/firebasestorage.googleapis.com/v0/b/recipe-app-1b76e.appspot.com/o /B74F604B-68FD-45BB-ABDB-150B03E83A2A.png?alt=media & token = ae2643c4-647 9-4dc8-b389-d04caac98392不存在。“ UserInfo = {object = https：/firebasestorage.googleapis.com/v0/b/recipe-app-1b76e.appspot.com/o/B74F604B-68FD-45BB-ABDB-150B03E83A2A.png？alt = media & token = ae2643c4- 6479-4dc8-b389-d04caac98392，bucket = recipe-app-1b76e.appspot.com，ResponseBody = { “error”：{ “code”：404, “message”：“Not Found。Could not delete object” } }，

Answer 1

解决了！下面有什么工作对我来说：

let storage = Storage.storage() 
let url = food[indexPath.row].downloadURL 
let storageRef = storage.reference(forURL: url) 

//Removes image from storage 
storageRef.delete { error in 
    if let error = error { 
     print(error) 
    } else { 
     // File deleted successfully 
    } 
} 

Answer 2

根据图像位置创建参考。

// Create a reference to the file to delete 
let imageRef = storageRef.child("image.png") 

// Delete the file 
imageRef.delete { error in 
    if let error = error { 
    // Uh-oh, an error occurred! 
    } else { 
    // File deleted successfully 
    } 
} 

以下行

food.remove(at: indexPath.row)

Storing/Downloading/Deleting images or videos Using Firebase Cloud Storage之前添加上面的代码！