如何sequently用awk

-1

读线

我的文件包含了这样的数据：如何sequently用awk

Line1 2016-03-16 01:12:26 17.70500 83.26889 11.90 
Line2 2016-03-16 01:22:36 17.70500 83.26889 11.90 
Line3 2016-03-16 01:42:25 17.70500 83.26889 11.90 
Line4 2016-03-16 01:42:36 17.70500 83.26889 11.90 
Line5 2016-03-16 02:12:25 17.70500 83.26889 11.90 
Line6 2016-03-16 02:12:35 17.70500 83.26889 11.90

我需要像一个时间比较行：

Line1 2016-03-16 01:12:26 17.70500 83.26889 11.90 
Line2 2016-03-16 01:22:36 17.70500 83.26889 11.90 

Line2 2016-03-16 01:12:26 17.70500 83.26889 11.90 
Line3 2016-03-16 01:22:36 17.70500 83.26889 11.90 

Line3 2016-03-16 01:12:26 17.70500 83.26889 11.90 
Line4 2016-03-16 01:22:36 17.70500 83.26889 11.90 

Line4 2016-03-16 01:12:26 17.70500 83.26889 11.90 
Line5 2016-03-16 01:22:36 17.70500 83.26889 11.90

来源

2016-03-17 Krishna Prasad

预期产出是什么？需要比较完整的产品线还是只有一些领域？ – Firefly

在第二个数据块中，您的行是前两个的重复项。 – karakfa

awk中，当然，已经顺序读取行没有任何额外的努力。对于这类问题，你要比较当前和以前行的信息，您可以使用模板，例如：

$ cat pcl.awk 
NR == 1 { prev_line = $0 } 

NR > 1 { 
    print "Previous: " prev_line 
    print "Current: " $0 
    print "(Comparison logic here)" 
    print "" 
    prev_line = $0; 
} 

$ awk -f pcl.awk pcl.txt 
Previous: Line1 2016-03-16 01:12:26 17.70500 83.26889 11.90 
Current: Line2 2016-03-16 01:22:36 17.70500 83.26889 11.90 
(Comparison logic here) 

Previous: Line2 2016-03-16 01:22:36 17.70500 83.26889 11.90 
Current: Line3 2016-03-16 01:42:25 17.70500 83.26889 11.90 
(Comparison logic here) 

Previous: Line3 2016-03-16 01:42:25 17.70500 83.26889 11.90 
Current: Line4 2016-03-16 01:42:36 17.70500 83.26889 11.90 
(Comparison logic here) 

Previous: Line4 2016-03-16 01:42:36 17.70500 83.26889 11.90 
Current: Line5 2016-03-16 02:12:25 17.70500 83.26889 11.90 
(Comparison logic here) 

Previous: Line5 2016-03-16 02:12:25 17.70500 83.26889 11.90 
Current: Line6 2016-03-16 02:12:35 17.70500 83.26889 11.90 
(Comparison logic here)

根据手头问题的具体情况，您可能希望保存一个或更具体的字段，例如$3，而不是整行（$0），但解决方案的一般形式或多或少是相同的。

来源

2016-03-17 12:09:58 jas

如何sequently用awk

回答

相关问题