CsvReader映射和转换：没有强制操作符

Question

首先，感谢您的时间。我正尝试第一次使用CsvHelper以及自定义类和自定义地图。我越来越

这里“没有cercion运算符类型‘System.Int32’和‘System.String’之间定义”是我的课：

class Vendor 
{ 
    public string VENDORID { get; set; } 
    public string VENDORNAME { get; set; } 
    public string VENDORSHORTNAME { get; set; } 
    public string VENDORCHECKNAME { get; set; } 
    public string HOLD { get; set; } 
    public string VENDORSTATUS { get; set; } 
    public string VENDORCLASSID { get; set; } 
    public string PRIMARYVENDORADDRESSID { get; set; } 
    public string VENDORCONTACT { get; set; } 
    public string ADDRESS1 { get; set; } 
    public string ADDRESS2 { get; set; } 
    public string ADDRESS3 { get; set; } 
    public string CITY { get; set; } 
    public string STATE { get; set; } 
    public string ZIPCODE { get; set; } 
    public string COUNTRYCODE { get; set; } 
    public string COUNTRY { get; set; } 
    public string PHONE1 { get; set; } 
    public string PHONE2 { get; set; } 
    public string PHONE3 { get; set; } 
    public string FAXNUMBER { get; set; } 
    public string VENDORACCOUNTNUMBER { get; set; } 
    public string PAYMENTTERMSID { get; set; } 
    public string TAXIDNUMBER { get; set; } 
    public string TAXREGISTRATIONNUMBER { get; set; } 
    public string USER_DEFINED1 { get; set; } 
    public string USER_DEFINED2 { get; set; } 
    public string TAX1099TYPE { get; set; } 
    public string TAX1099BOXNUMBER { get; set; } 
    public string PURCHASESACCOUNT { get; set; } 
    public string TRANSITROUTINGNUMBER { get; set; } 
    public string EFTBANKACCOUNTNUMBER { get; set; } 
} 

class VendorMap : CsvClassMap<Vendor> 
{ 
    public override void CreateMap() 
    { 
     Map(m => m.VENDORID).Name("Vendor ID"); 
     Map(m => m.VENDORNAME).Name("Vendor name"); 
     Map(m => m.VENDORSHORTNAME).Name("Vendor short name"); 
     Map(m => m.VENDORCHECKNAME).Name("Vendor check name"); 
     Map(m => m.HOLD).Name("Hold").Default(1); 
     Map(m => m.VENDORSTATUS).Name("Vendor status").Default("Active"); 
     Map(m => m.VENDORCLASSID).Name("Vendor class ID"); 
     Map(m => m.PRIMARYVENDORADDRESSID).Name("Primary vendor address ID"); 
     Map(m => m.VENDORCONTACT).Name("Vendor contact"); 
     Map(m => m.ADDRESS1).Name("Address 1"); 
     Map(m => m.ADDRESS2).Name("Address 2"); 
     Map(m => m.ADDRESS3).Name("Address 3"); 
     Map(m => m.CITY).Name("City"); 
     Map(m => m.STATE).Name("State"); 
     Map(m => m.ZIPCODE).Name("Zip Code"); 
     Map(m => m.COUNTRYCODE).Name("Country code"); 
     Map(m => m.COUNTRY).Name("Country"); 
     Map(m => m.PHONE1).Name("Phone 1"); 
     Map(m => m.PHONE2).Name("Phone 2"); 
     Map(m => m.PHONE3).Name("Phone 3"); 
     Map(m => m.FAXNUMBER).Name("Fax number"); 
     Map(m => m.VENDORACCOUNTNUMBER).Name("Vendor account number"); 
     Map(m => m.PAYMENTTERMSID).Name("Payment terms ID"); 
     Map(m => m.TAXIDNUMBER).Name("Tax ID number"); 
     Map(m => m.TAXREGISTRATIONNUMBER).Name("Tax registration number"); 
     Map(m => m.USER_DEFINED1).Name("User-defined 1"); 
     Map(m => m.USER_DEFINED2).Name("User-defined 2"); 
     Map(m => m.TAX1099TYPE).Name("Tax 1099 type:"); 
     Map(m => m.TAX1099BOXNUMBER).Name("Tax 1099 box number"); 
     Map(m => m.PURCHASESACCOUNT).Name("Purchases account"); 
     Map(m => m.TRANSITROUTINGNUMBER).Name("Transit Routing Number"); 
     Map(m => m.EFTBANKACCOUNTNUMBER).Name("EFT Bank Account Number"); 
    } 
} 

这里就是我读文件：

CsvReader csv = new CsvReader(reader); 

csv.Configuration.HasHeaderRecord = true; 
csv.Configuration.RegisterClassMap<VendorMap>(); 

List<Vendor> vendors = null; 

try 
{ 
    vendors = csv.GetRecords<Vendor>().ToList(); 

理想情况下，我希望HOLD，TAX99TYPE和TAX99BOXNUMBER属性类型为“short”。但是，由于我收到错误“无法执行转换”。

这里是我的测试CSV的一部分：

"Vendor ID","Vendor name","Vendor short name","Vendor check name","Hold","Vendor status","Vendor clas 
"AA0011","UAT Demo","","","","Active","","Residence","Demo UAT","TESTING","TESTING","","TESTING","KS" 
"AA0011","UAT Demo","","","","Active","","Supply","Demo UAT","NEW ADDRESS","NEW ADDRESS","","NEW ADDR 

Answer 1

问题本质上是由列定义的类型（串）的不匹配造成的：

public string HOLD { get; set; } 

，它的默认值（Int32）已，

Map(m => m.HOLD).Name("Hold").Default(1); 

据我所知，与当前版本的CsvHelper，默认值类型应该匹配其相应列的类型定义。

您有两种选择。将列HOLD定义为short，或将默认值更改为字符串（即"1"）。

假设你已经尝试过的一种方式，在错误“的转换不能执行”可能意味着在你的CSV一个或多个列值文件 包含不能转换为short的值（即字母数字值）。