1
我想为我的服务器创建一个登录系统。我使用xampp为本地网站使用了类似的代码,但现在我正在尝试使用外部服务器。我得到的错误是这个。登录系统的sqlserver连接错误
Array([0] => Array([0] => 42000 [SQLSTATE] => 42000 [1] => 102 [code] => 102 [2] => [ODBC] 11为SQL Server] [SQL服务器]附近有语法错误
'. [message] => [Microsoft][ODBC Driver 11 for SQL Server][SQL Server]Incorrect syntax near '
'))
,我的代码如下:
<?php
session_start();
$inputuser = $_REQUEST['Username'];
$inputpass = $_REQUEST['Password'];
$Server = "MyServer";
$user = "user";
$password = "pass";
$database = "mydb";
$table = "users";
$connectionInfo = array("Database"=>$database,"UID"=>$user, "PWD"=>$password);
$link = sqlsrv_connect($Server, $connectionInfo);
if ($link === false) {
echo "Connection failed. \n";
die(print_r(sqlsrv_errors(), true));
}
$query = "SELECT `Username` FROM `onlinereporting` . `users` WHERE `Username` = '$inputuser'";
$querypass = "SELECT `Password` FROM `onlinereporting` . `users` WHERE `Password` ='$inputpass'";
$result = sqlsrv_query($link,$query);
$resultpass = sqlsrv_query($link,$querypass);
if ($result === false) {
die(print_r(sqlsrv_errors(), true));
}
$row = sqlsrv_fetch_array($result);
$rowpass = sqlsrv_fetch_array($resultpass);
$serveruser = $row["Username"];
$serverpass = $rowpass["Password"];
if ($serveruser And $serverpass) {
header('Location: index.html');
}
else {
header('Location: FailedPage.html');
}
?>
连接工作正常,当我尝试发生的唯一问题检查结果是否为假。
当我不试图检查$结果时,我插入的所有内容都被视为错误的用户名和密码。
欢迎任何帮助或建议。
现在误差改变,它看起来像这样: 阵列([0] =>数组([0] => 42000 [SQLSTATE] => 42000 [ 1] => 102 [code] => 102 [2] => [Microsoft] [用于SQL Server的ODBC驱动程序11] [SQL Server] [用户]附近的语法错误[message] => [Microsoft]对于SQL Server] [SQL Server]'users'附近的语法不正确。)) –