下面的代码
String myString = "0067711990999999*1955*0515070999999999999N9+01*23*1+99999999";
// matches all number series (one or more consecutive digits)
// between * characters. * normally matches any character and
// so has to be escaped using \, which in a string becomes \\,
// i.e the regular expression is actually \*([0-9])\*
Pattern pattern = Pattern.compile("\\*([0-9]+)\\*");
Matcher matcher = pattern.matcher(myString);
while (matcher.find()) {
// the parantheses in the regex creates a capturing group, i.e.
// a substring within the match that can later be extracted.
// the "1" here means we're picking up the value of the first
// (and in this case, only) capturing group, which is the
// actual numbers (i.e. not including the * characters)
System.out.println(matcher.group(1));
}
将打印
1955
23
这就是你想要的?
在这种情况下,什么是“大胆”数字? – claesv 2012-04-24 06:51:19
一年以上** 1955 *和温度* 23 *。 – 2012-04-24 06:55:29
字体更改本身不是字符。也许你原始形式的输入有某种顺序,表示字体改变;你可以确定它的顺序和匹配。请注意,如果这个序列是HTML,那么解析可能会出错;除了匹配HTML标签的常见问题之外,您可能需要担心CSS。 – geekosaur 2012-04-24 06:59:06