UPDATE SELECT JOIN

Question

我的两难困境是，我需要将我的事务表中的subscription_id更新为基于相同billerid的新subscription_id。

我的订阅表具有来自不同账单的多个订阅记录的成员。我很难把这个更新选择/连接到一起在MySQL上。

TBL subscription_id

 
+--------------------+---------------+----------+ 
| subscription_id | memberid  | billerid | 
+--------------------+---------------+----------+ 
12345    | A    | ?  | 
+--------------------+---------------+----------+ 
67890    | A    | 13  | 
+--------------------+---------------+----------+ 
11222    | B    | 13  | 
+--------------------+---------------+----------+ 
91422    | B    | ?  | 
+--------------------+---------------+----------+ 

TBL交易

 
+---------------+-----------------+----------+ 
| trans_id  | subscription_id | billerid | 
+---------------+-----------------+----------+ 
00012   | 12345   | 13  | 
+---------------+-----------------+----------+ 
02013   | 12345   | 13  | 
+---------------+-----------------+----------+ 
08013   | 11222   | 13  | 
+---------------+-----------------+----------+ 
50013   | 11222   | 13  | 
+---------------+-----------------+----------+ 

Answer 1

UPDATE transaction AS t 
JOIN (SELECT s1.subscription_id AS old_subid, 
      s2.subscription_id AS new_subid, 
      s2.billerid AS billerid 
     FROM subscription_id AS s1 
     JOIN subscription_id AS s2 ON s1.memberid = s2.memberid 
     WHERE s1.billerid = '?' 
     AND s2.billerID != '?') AS s 
ON t.billerid = s.billerid AND t.subscription_id = s.old_subid 
SET t.subscription_id = s.new_subid 

DEMO

我想，我想出了一个适合您的最新评论一个简单的版本：

UPDATE transaction AS t 
JOIN subscription_id AS s1 
    ON s1.subscription_id = t.subscription_id 
     AND s1.billerid != t.billerid 
JOIN subscription_id AS s2 
    ON s1.memberid = s2.memberid 
     AND s2.subscription_id != s1.subscription_id 
     AND s2.billerid = t.billerid 
SET t.subscription_id = s2.subscription_id 

DEMO