jpgrid php json_encode（）关联数组

我刚开始使用jpgrid。我有这个问题与PHP json_encode。jpgrid php json_encode（）关联数组

根据来自jqGrid的网站的示例中，可以通过PHP代码来生成的JSON字符串类似如下：

$responce->page = "1"; 
    $responce->total = 1; 
    $responce->records = "1"; 

    $i=1; $amttot=0; $taxtot=0; $total=0; 
    while($i<=10) { 
     $amttot += $row[amount]; 
     $taxtot += $row[tax]; 
     $total += $row[total]; 
     $responce->rows[$i]['id']=strval($i); 
     $responce->rows[$i]['cell']=array("123","2012-10-15","name","10000","tax","9999","note"); 
     $i++; 
    } 
    $responce->rows = (array)$responce->rows; 
    $responce->userdata['amount'] = $amttot; 
    $responce->userdata['tax'] = $taxtot; 
    $responce->userdata['total'] = $total; 
    $responce->userdata['name'] = 'Totals:';

我有问题

$responce->rows[$i]['id']=strval($i); 
    $responce->rows[$i]['cell']=array("123","2012-10-15","name","10000","tax","9999","note");

当PHP json_encode产生json字符串，rows数组被视为关联数组。因此json字符串的结果如下所示：

{"page":"1","total":1,"records":"1", 
"rows":{"1":{"id":"1","cell":["123","2012-10-15","name","10000","tax","9999","note"]}, 
     "2":{"id":"2","cell":["123","2012-10-15","name","10000","tax","9999","note"]}, 
     "3":{"id":"3","cell":["123","2012-10-15","name","10000","tax","9999","note"]}, 
     "4":{"id":"4","cell":["123","2012-10-15","name","10000","tax","9999","note"]}, 
     "5":{"id":"5","cell":["123","2012-10-15","name","10000","tax","9999","note"]}, 
     "6":{"id":"6","cell":["123","2012-10-15","name","10000","tax","9999","note"]}, 
     "7":{"id":"7","cell":["123","2012-10-15","name","10000","tax","9999","note"]}, 
     "8":{"id":"8","cell":["123","2012-10-15","name","10000","tax","9999","note"]}, 
     "9":{"id":"9","cell":["123","2012-10-15","name","10000","tax","9999","note"]}, 
     "10":{"id":"10","cell":["123","2012-10-15","name","10000","tax","9999","note"]}}, 
"userdata":{"amount":0,"tax":0,"total":0,"name":"Totals:"}}

此json字符串不能由jqgrid处理。实际上jqgrid不会引发任何javascript错误。它只是不呈现表格内容。我看了一下jqgrid示例网站中的json字符串，通过firebugs。它看起来像这样：

{"page":"1","total":2,"records":"13", 
"rows":[{"id":"13","cell":["13","2007-10-06","Client 3","1000.00","0.00","1000.00",null]}, 
     {"id":"12","cell":["12","2007-10-06","Client 2","700.00","140.00","840.00",null]}, 
     {"id":"11","cell":["11","2007-10-06","Client 1","600.00","120.00","720.00",null]}, 
     {"id":"10","cell":["10","2007-10-06","Client 2","100.00","20.00","120.00",null]},   
     {"id":"9","cell":["9","2007-10-06","Client 1","200.00","40.00","240.00",null]}, 
     {"id":"8","cell":["8","2007-10-06","Client 3","200.00","0.00","200.00",null]}, 
     {"id":"7","cell":["7","2007-10-05","Client 2","120.00","12.00","134.00",null]}, 
     {"id":"6","cell":["6","2007-10-05","Client 1","50.00","10.00","60.00",""]}, 
     {"id":"5","cell":["5","2007-10-05","Client 3","100.00","0.00","100.00","no tax at all"]}, 
     {"id":"4","cell":["4","2007-10-04","Client 3","150.00","0.00","150.00","no tax"]}], 
     "userdata":{"amount":3220,"tax":342,"total":3564,"name":"Totals:"}}

我不能找出如何能够使用所述关联阵列PHP示例代码来生成这样的阵列OBJ JSON字符串内。我正在使用php 5.4

我可以改变jqgrid或php来做这项工作？我很惊讶没有人有这个问题。我可能会错过一些相当明显的东西。

感谢

casbby

来源

2012-10-15 casbby

问题是由响应数组对象是如何在PHP产生引起的。当我最初在循环中创建数组时，我从1开始索引而不是0. Response-> rows [i] 这导致php将响应数组视为关联而不是顺序。因此PHP放入响应对象的名称值的对象（而我试图创建非命名对象的数组）

的解决方案是，以确保数组的索引是顺序和连续

来源

2012-10-17 20:39:09 casbby

jpgrid php json_encode（）关联数组

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