提取某些字符串，并将其分配给相邻列

Question

我有一个类似的表：

with tab as(
select 'P710345,P345123 are not valid' m from dual 
union all 
select 'P9,P234098,P675001 are not valid' m from dual) 
select * from tab 

我需要的是提取与P开头的字符串，并将这些字符串放到新列在同一排。

最终结果：

P710345,P345123 are not valid   | P710345 | P345123 |  | 
P9,P234098,P675001 are not valid | P9| P234098 |P675001 | 

我试图与regexp_substr提取：

with tab as(
select 'P710345,P345123 are not valid' m from dual 
union all 
select 'P9,P234098,P675001 are not valid' m from dual) 
select regexp_substr (m,'P\d\w+','2') b from tab 

我目前在这里停留。

Answer 1

我发现最简单的解决方法是做一个CSV文件，然后导入或在speedsheet程序使用它在一列

SELECT CONCAT(
    "'", m, "';'", 
    REPLACE(
    SUBSTR(m, 1, POSITION(' ' IN m)), 
    ',', 
    "';'"), 
    "';") 
FROM (SELECT 'P710345,P345123 are not valid' AS m FROM DUAL UNION ALL SELECT 'P9,P234098,P675001 are not valid' AS m FROM DUAL) AS t;