SQL SELECT MAX（COUNT）

Question

我想选择谁拥有用户的最大数微观柱：

SELECT "name", count(*) FROM "users" 
    INNER JOIN "microposts" ON "microposts"."user_id" = "users"."id" 
    GROUP BY users.id 

，这将返回

"Delphia Gleichner";15 
"Louvenia Bednar IV";10 
"Example User";53 
"Guadalupe Volkman";20 
"Isabella Harvey";30 
"Madeline Franecki II";40 

但我只想选择"Example User";53，（用户谁有MAX微博计数）

我试图添加HAVING MAX(count*)，但这没有奏效。

Answer 1

我想尝试用ORDER BY最大DESC LIMIT 1，其中最大的是COUNT（*）领域。喜欢的东西：

SELECT "name", count(*) maximum FROM "users" 
    INNER JOIN "microposts" ON "microposts"."user_id" = "users"."id" 
GROUP BY users.id 
ORDER BY maximum DESC 
LIMIT 1 

我不”具有的MySQL现在，所以我在纸上做这（和它可能无法正常工作），但它只是一个方向。

Answer 2

也许是这样的：

SELECT "name", count(*) 
FROM "users" 
INNER JOIN "microposts" ON "microposts"."user_id" = "users"."id" 
GROUP BY users.id 
HAVING COUNT(microposts) = (SELECT COUNT(microposts) 
         FROM users 
         GROUP BY microposts 
         ORDER BY COUNT(microposts) DESC 
         LIMIT 1) 

没有测试它，但它可能工作

Answer 3

SELECT TOP 1 "name", count(*) AS ItemCount FROM "users" 
INNER JOIN "microposts" ON "microposts"."user_id" = "users"."id" 
GROUP BY users.id 
ORDER BY ItemCount DESC 

Answer 4

SELECT x.name, MAX(x.count) 
FROM (
SELECT "name", count(*) 
    FROM "users" INNER JOIN "microposts" ON "microposts"."user_id" = "users"."id" 
    GROUP BY users.id 
) x 

Answer 5

这很简单，你可以尝试：

SELECT "name", MAX(count_num) FROM 
(SELECT "name", count(*) as count_num 
FROM "users" INNER JOIN "microposts" ON "microposts"."user_id" = "users"."id" 
GROUP BY users.id) x