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这是我的问题。我正在设置日历,并且无法从sqlite数据库切换到我的mysql数据库。无法从mysql数据库加载数据
问题是DayPilot在从mysql传递时没有加载事件。非常感谢任何帮助。谢谢。
<?php
//$db_exists = file_exists("daypilot1.sqlite");
//$db = new PDO('sqlite:daypilot.sqlite'); This works
// i tried these two ways. both of them did not work.
$db = new PDO("mysql:host=localhost;dbname=his", "root", "123");
/* $servername = "localhost";
$username = "root";
$password = "123";
try {
$db = new PDO("mysql:host=$servername;dbname=his", $username, $password);
echo "Connected successfully";
}
catch(PDOException $e)
{
echo $e->getMessage();
}
*/
if (!$db) {
//create the database
$db->exec("CREATE TABLE IF NOT EXISTS events (
id INTEGER PRIMARY KEY,
name TEXT,
start DATETIME,
end DATETIME,
resource VARCHAR(30))");
$messages = array(
array('name' => 'Event 1',
'start' => '2013-05-09T00:00:00',
'end' => '2013-05-09T10:00:00',
'resource' => 'B')
);
$insert = "INSERT INTO events (name, start, end, resource) VALUES (:name, :start, :end, :resource)";
$stmt = $db->prepare($insert);
$stmt->bindParam(':name', $name);
$stmt->bindParam(':start', $start);
$stmt->bindParam(':end', $end);
$stmt->bindParam(':resource', $resource);
foreach ($messages as $m) {
$name = $m['name'];
$start = $m['start'];
$end = $m['end'];
$resource = $m['resource'];
$stmt->execute();
}
}
?>
此代码中的更改是什么?这是原始代码 – Priyankara
Anayway寻求你的回应 – Priyankara
@ user2781812'$ stmt-> execute();'从循环中退出并且'$ stmt-> bindParam'在循环之后。 –