2012-02-27 101 views
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我们正在为我们的iPad项目使用SQLite。我们正在从另一个SQLite导入数据。导入数据后,我们无法将数据从viewcontroller插入到Sqlite中。 当我们尝试访问设备中的相同内容时抛出一个错误,而在模拟器中正常工作。将数据导入到Sqlite3

Error from Device: * Assertion failure in -[DataBaseSharedManager insertLoginDetails:], /Users/vidya/Desktop/eDetail_feb27/eDetail/Classs/Database files/DataBaseSharedManager.m:165 Feb 27 18:07:17 unknown eDetail[1866] : Terminating app due to uncaught exception 'NSInternalInconsistencyException', reason: 'Error:failed to save priority with message 'database disk image is malformed'' ** First throw call stack: (0x33e758bf 0x352901e5 0x33e757b9 0x3289f3b3 0x336b15 0xae887 0x33dd422b 0x32fd8b 0x328fcc39 0x328546e9 0x328546b3 0x328545d5 0x375048a5 0x374f9545 0x374f9639 0x374f9243 0x374f9179 0x33e49b03 0x33e492cf 0x33e48075 0x33dcb4dd 0x33dcb3a5 0x306b6fcd 0x32393743 0xab125 0xab0bc)

注意:我们的SQlite文件是36MB。

代码以供参考:

NSArray *paths     = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES); 
    NSString *documentsDirectory = [paths objectAtIndex:0]; 
    NSString *writableDBPath  = [documentsDirectory stringByAppendingPathComponent:@"eTest.sqlite"]; 


    if (sqlite3_open([writableDBPath UTF8String], &database) == SQLITE_OK){ 

     NSString *sSqlSelect = [NSString stringWithFormat:@"Insert into LOGIN (LoginId, UserName, Password, LastSyncDate, SFId,SecurityToken, AccountType, SFUserId,Region,ModifiedDate) values (\"%@\", \"%@\", \"%@\", \"%@\", \"%@\", \"%@\", \"%@\", \"%@\", \"%@\", \"%@\")", [pDict objectForKey:@"LoginId"],[pDict objectForKey:@"UserName"],[pDict objectForKey:@"Password"],[pDict objectForKey:@"LastSyncDate"],[pDict objectForKey:@"SFId"],[pDict objectForKey:@"SecurityToken"], [pDict objectForKey:@"AccountType"], [pDict objectForKey:@"SFUserId"],[pDict objectForKey:@"Region"],[pDict objectForKey:@"ModifiedDate"]]; 

     sqlite3_stmt *insertValue; 
     int nResult = sqlite3_prepare_v2(database, [sSqlSelect UTF8String],-1,&insertValue,NULL); 
     if(nResult == SQLITE_OK){ 
      sqlite3_step(insertValue); 
     }else{ 
      NSAssert1(0,@"Error:failed to save priority with message '%s'",sqlite3_errmsg(database)); 
     } 
     sqlite3_finalize(insertValue); 
    }else{ 
     sqlite3_close(database); 
     NSAssert1(0, @"Failed to open database with message '%s'.", sqlite3_errmsg(database)); 
    } 

对于交易:我们正在从一个的SQLite中的数据导出和导入同一个表到另一个SQLite的。我们正在使用Firefox SQLite Manager进行此操作。

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请帮助我们找到上述问题的解决方案.. – 2012-02-27 12:42:37

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你能告诉哪一行它是异常吗? – NSCry 2012-02-27 14:01:18

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NSAssert1(0,@“无法用消息'%s'打开数据库。”,sqlite3_errmsg(database)); – Deepthi 2012-02-27 14:03:31

回答

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我认为当你使用firefox导入数据库时​​,它会被破坏。

我认为你可以通过编码从一个sqlite文件中读取数据并将其存储为另一个sqlite文件来完成这件事。你可以为它分别制作一个简短的代码,然后在主包中复制并粘贴sqlite文件。

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是的......有没有其他方法可以做到这一点? – Deepthi 2012-02-28 06:42:54

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创造了iPad的手段? – NSCry 2012-02-28 10:46:44

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创建ipa并在实际设备上运行,它工作正常。当我尝试运行连接到机器的应用程序时,它崩溃了。 - – Deepthi 2012-02-29 05:09:04