我有一个问题,我不能链接我打开的按钮“打开”命令,请帮助!打开文件按钮 - Python的Tkinter
Error= fileName = tkFileDialog.askopenfilename()
NameError: global name 'tkFileDialog' is not defined
我有什么:
from Tkinter import *
from tkFileDialog import askopenfilename
frm = Frame(parent)
frm.pack(fill=X)
Button(frm, text=' Browse ', command=self.getFileName).pack(side=LEFT)
def getFileName(self):
fileName = tkFileDialog.askopenfilename()
iconEntry.insert(0, fileName)
SimpleEditor().mainloop()
谢谢,它的工作! – user3176943