如何在Spock中返回Long的存根方法？

Question

我一直在尝试存根方法返回Long，但我所得到的是null。有没有办法做到这一点？

interface Clock { 
    Long currentTimeMillis(); 
} 

def "stub method returning long"() { 
    Clock clock = Mock(Clock) 
    clock.currentTimeMillis() >> 1 

    when: 
    Long currentTime = clock.currentTimeMillis() 

    then: 
    currentTime == 1 
    1 * clock.currentTimeMillis() 
} 

def "mock method returning longs"() { 
    Clock clock = Mock(Clock) 
    clock.currentTimeMillis() >>> [1, 2, 3] 

    when: 
    Long currentTime = clock.currentTimeMillis() 

    then: 
    currentTime == 1 
    1 * clock.currentTimeMillis() 
} 

在两个测试中我发现了以下错误：

Condition not satisfied: 

    currentTime == 1 
    |   | 
    null  false 

Answer 1

即使你们俩模拟和记录的行为，应定义如下。

下面是它如何工作的：

@Grab('org.spockframework:spock-core:0.7-groovy-2.0') 
@Grab('cglib:cglib-nodep:3.1') 

import spock.lang.* 


class Test extends Specification { 
    def "stub method returning long"() { 
     given: 
     Clock clock = Mock(Clock) 

     when: 
     Long currentTime = clock.currentTimeMillis() 

     then: 
     currentTime == 1 
     1 * clock.currentTimeMillis() >> 1 
    } 

    def "mock method returning longs"() { 
     given: 
     Clock clock = Mock(Clock) 

     when: 
     Long currentTime = clock.currentTimeMillis() 

     then: 
     currentTime == 1 
     1 * clock.currentTimeMillis() >>> [1, 2, 3] 
    } 
} 

interface Clock { 
    Long currentTimeMillis(); 
}