如何在单词之间添加分隔符？

Question

我正在为我的作业写一个hang子手程序，并遇到一个小问题。 在我的程序中，为了分开单词，我使用'|'符号。 例如这是这个词来猜测：

U N I T E D | S T A T E S | O F | A M E R I C A 

我有显示没有一个StringBuffer变量。破折号 这里，

_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ 

我试着用下面的代码插入分隔符“|”

if(guessword.indexOf('|') == -1) 
    System.out.print(" "); 
else 
    guessit.setCharAt(guessword.indexOf('|'),'|'); 

我知道它错了，它只插入1个分隔符。 你能帮我把分离器插在正确的位置吗？ 也可以尝试删除System.out.print（“”）;因为它不必要地留下空间。 我可以使用break吗？而不是 对于上述例如我得到的显示器作为

_ _ _ _ _ _ | _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ 

其实我是想

_ _ _ _ _ _ | _ _ _ _ _ _ | _ _ | _ _ _ _ _ _ _ 

我的主要方法如下

public static void main()throws IOException 
{ 
    Hangman obj = new Hangman(); 
    InputStreamReader isr = new InputStreamReader(System.in); 
    BufferedReader br = new BufferedReader(isr); 
    PrintWriter p = new PrintWriter(System.out,true); 

    p.println("Lets play HANGMAN"); 
    p.println(); 
    p.println("Enter your choice according to the following options.\n 
       NOTE: Words are related to the topics given below.\n 
       1. Sports\n2. Movies\n3. Computer\n4. Food\n5. Countries"); 
    p.println(); 
    int choice = Integer.parseInt(br.readLine()); 
    obj.clearScreen(); 
    String bothwordandclue[] = new String[2]; 

    if(choice == 1) 
     bothwordandclue = obj.Sports(); 
    else if(choice == 2) 
     bothwordandclue = obj.Movies(); 
    else if(choice == 3) 
     bothwordandclue = obj.Computers(); 
    else if(choice == 4) 
     bothwordandclue = obj.Food(); 
    else if(choice == 5) 
     bothwordandclue = obj.Countries(); 
    else 
     p.println("Wrong choice"); 

    int counter = 6; 
    String guessword = bothwordandclue[0]; 
    String wordclue = bothwordandclue[1]; 

    int lengthofword = (int)(Math.round(((double)guessword.length()/2))); 
    int checkguess = 0; 
    String a; 
    StringBuffer guessit = new StringBuffer(); 

    for (int i = 0;i < lengthofword; i++) 
     guessit = guessit.append("_ "); 

    guessit.delete((2 * lengthofword)-1,(2 * lengthofword)); 

    if(guessword.indexOf('|') == -1) 
     System.out.print(" "); 
    else 
     guessit.setCharAt(guessword.indexOf('|'),'|'); 

    p.println(guessit); 
    do 
    { 
     p.println(); 
     p.println("Enter your guess letter in capitals"); 
     String guessletter = br.readLine(); 
     obj.clearScreen(); 

     for(int i = 0;i<lengthofword;i++) 
     { 
      if(guessletter.charAt(0) == guessword.charAt(2*i)) 
      { 
       guessit.setCharAt(2*i,guessletter.charAt(0)); 
       checkguess=1; 
      }     
     } 
     if(checkguess == 1) 
     { 
      p.println("Correct Guess"); 
      p.println(guessit); 
     } 
     else 
     { 
      counter--; 
      p.println("Wrong guess. You have " + counter + 
            " incorrect guesses left"); 
      p.println(guessit); 
     } 
     checkguess = 0; 
     a = guessit.toString(); 
     if(a.equals(guessword)) 
     { 
      p.println("You guessed the word!!!!!"); 
      counter=0; 
     }   
    }while(counter>0); 
} 

Answer 1

只能与indexOf做到这一点。只需要使用该方法的另一个版本，即可从哪里开始搜索。见你需要的String#indexOf(String str, int fromIndex)。

int index = guessword.indexOf("|"); 
while(index >= 0) { 
    guessIt.setCharAt(index, '|') 

    // Start searching for next "|" after this index 
    index = guessword.indexOf("|", index+1)); 
} 

Answer 2

见String.replaceAll

如果你不知道正则表达式：

Regular expression on wikipedia

Regular expression cheat sheet

Answer 3

的问题是，setCharAt和indexOf只适用于每一个指标，这就是为什么它只是更换第一|。您将不得不多次遍历guessword。您可以使用一些Java的其他内置字符串函数或使用一个简单的for循环，即

for(int i = 0; i < guessword.length(); i++){ 
    if(guessword.charAt(i) == '|') 
     guessit.setCharAt(i, '|'); 
}