嵌套for循环与2维数组

Question

我如何可以替换数组中的数字，可以乘以2字符串“偶数”，也可以“奇数”。

var numbers = [ 
 
    [243, 12, 23, 12, 45, 45, 78, 66, 223, 3], 
 
    [34, 2, 1, 553, 23, 4, 66, 23, 4, 55], 
 
    [67, 56, 45, 553, 44, 55, 5, 428, 452, 3], 
 
    [12, 31, 55, 445, 79, 44, 674, 224, 4, 21], 
 
    [4, 2, 3, 52, 13, 51, 44, 1, 67, 5], 
 
    [5, 65, 4, 5, 5, 6, 5, 43, 23, 4424], 
 
    [74, 532, 6, 7, 35, 17, 89, 43, 43, 66], 
 
    [53, 6, 89, 10, 23, 52, 111, 44, 109, 80], 
 
    [67, 6, 53, 537, 2, 168, 16, 2, 1, 8], 
 
    [76, 7, 9, 6, 3, 73, 77, 100, 56, 100] 
 
]; 
 

 
for (var i = 0; i < numbers.length; i++) { 
 
    for (var j = 0; j < numbers[i].length; j++) { 
 
    if(numbers[i][j] % 2 === 0) { 
 
     numbers[i][j] += " even"; 
 
    } else { 
 
     numbers [i][j] += " odd"; 
 
    } 
 
    
 
    console.log(numbers[j][i]); 
 
    } 
 
}

Answer 1

你需要切换的指数，显示实际的元素。如果没有，你会得到一些没有改变值的元素。

console.log(numbers[i][j]); 
//    ^^ 

var numbers = [ 
 
    [243, 12, 23, 12, 45, 45, 78, 66, 223, 3], 
 
    [34, 2, 1, 553, 23, 4, 66, 23, 4, 55], 
 
    [67, 56, 45, 553, 44, 55, 5, 428, 452, 3], 
 
    [12, 31, 55, 445, 79, 44, 674, 224, 4, 21], 
 
    [4, 2, 3, 52, 13, 51, 44, 1, 67, 5], 
 
    [5, 65, 4, 5, 5, 6, 5, 43, 23, 4424], 
 
    [74, 532, 6, 7, 35, 17, 89, 43, 43, 66], 
 
    [53, 6, 89, 10, 23, 52, 111, 44, 109, 80], 
 
    [67, 6, 53, 537, 2, 168, 16, 2, 1, 8], 
 
    [76, 7, 9, 6, 3, 73, 77, 100, 56, 100] 
 
]; 
 
for (var i = 0; i < numbers.length; i++) { 
 
    for (var j = 0; j < numbers[i].length; j++) { 
 
    if (numbers[i][j] % 2 === 0) { 
 
     numbers[i][j] += " even"; 
 
    } else { 
 
     numbers[i][j] += " odd"; 
 
    } 
 
    console.log(numbers[i][j]); 
 
    } 
 
}

Answer 2

如果你的意思是更换由弦数，你可以这样做，但数组必须定义为任何：

const numbers: any = [ 
    [243, 12, 23, 12, 45, 45, 78, 66, 223, 3], 
    [34, 2, 1, 553, 23, 4, 66, 23, 4, 55], 
    [67, 56, 45, 553, 44, 55, 5, 428, 452, 3], 
    [12, 31, 55, 445, 79, 44, 674, 224, 4, 21], 
    [4, 2, 3, 52, 13, 51, 44, 1, 67, 5], 
    [5, 65, 4, 5, 5, 6, 5, 43, 23, 4424], 
    [74, 532, 6, 7, 35, 17, 89, 43, 43, 66], 
    [53, 6, 89, 10, 23, 52, 111, 44, 109, 80], 
    [67, 6, 53, 537, 2, 168, 16, 2, 1, 8], 
    [76, 7, 9, 6, 3, 73, 77, 100, 56, 100] 
]; 

for (let i = 0; i < numbers.length; i++) { 
    for (let j = 0; j < numbers[i].length; j++) { 
    if (numbers[i][j] % 2 === 0) { 
     numbers [i][j] = 'even'; 
    } else { 
     numbers [i][j] = 'odd'; 
    } 
    } 
}