GOAL使用切换case语句:回音映射switch语句的情况下/匹配“postType”
问题:无论我怎么努力,在$ _ POST数据似乎消失,因此switch语句默认情况下会被触发,并且表单会再次显示,而不是我希望基于$ filter变量中包含的postType显示的预期/期望的echo语句。我在PHP 5.4工作
甲的var_dump返回: 阵列(2){[ “postType”] => NULL [ “为myContent”] =>串(4) “的DSF”}
相信我的表单和switch语句的语法/格式都正确。我的问题,我想是在某处的数据是如何或通过filter_input_array没有被传递到开关(INPUT_POST,[...])
愚见代码存根:
//test data
//$_POST = [ 'postType' => 'myPlayby', 'myContent' => 'Anna King', ];
//build the array of data created by from for switch checks
$filter = filter_input_array(INPUT_POST, [ 'postType' => [], 'myContent' => [], ]);
var_dump($filter);
echo "<br /><br />";
//$search = false;
switch ($filter['postType'])
{
case 'myChar':
echo "Character Check: " . $filter['myCharacter'];
$search = $filter['myCharacter'];
break;
//test data ought to trigger myPlayby case showing 'Playby check: Anna King' here... frack
case 'myPlayby':
echo "Playbe Check: " . $filter['myPlayby'];
$search = $filter['myPlayby'];
break;
case 'myFoobar':
echo "Foo Check: " . $filter['myFooBar'];
$search = $filter['myFooBar'];
break;
default:
echo '<form type="submit" method="post" action="' . THIS_PAGE . '"; >
<select name="postTypes">
<option default disable>-------------</option>
<option value="myChar">Character</option>
<option value="myPlayby">Playby</option>
<option value="myFooBar">Foo</option>
</select>
<input type="text" value="" name="myContent"/>
<input type="submit" name="submit" value="Submit">
</form>' ;
break;
}
这是我第一次使用filter_input_array处理$ _POST数据,经过一天的试用,错误,研究和努力,其中包括看Lynda.com,搜索Google和阅读我在StackOverflow上找到的相关帖子,php.net等,我迷失了方向。