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我知道还有其他类可以使用,但是我想使用LWP。这里接受的答案(How do I make parallel HTTP requests in Perl, and receive them back in order?)做我想要的,但我需要“标记”线程,以便我可以匹配请求与响应。我已经修改了代码如下:在Perl中为异步HTTP请求线程“标记”
#Setup and query the DB:
#hold all response\id pairs
my @response_bundles;
while (my @row = $query->fetchrow_array()) {
my $id = $row[0];
my $url = $row[1];
push @threads, async {
my @container_hash;
$container_hash[0] = @row;
$container_hash[1] = $ua->get($url);
push @response_bundles, @container_hash;
};
}
#Once this loop terminates all threads are done
for my $thread (@threads) {
$thread->join;
}
#Since all threads are completed we can now sort through the response bundles
for my $response_bundle (@response_bundles) {
print "test\n";
}
我的目标是踢一串HTTP请求和存储他们($ ID,$回应)对在数组中。我将它们全部推入异步过程,并且async {}中的子应该这样做(但不是)。我遍历线程数组,一旦完成,所有线程都应该完成。然后我通过我的捆绑和做的事情,但“打印测试”从来没有射击。我在想这个错吗?
编辑:
每我试图返回值的评论,但是这并不工作,要么
while (my @row = $query->fetchrow_array()) {
my $id = $row[0];
my $url = $row[1];
push @threads, async {
my @container_hash;
$container_hash[0] = @row;
$container_hash[1] = $ua->get($url);
return @container_hash;
};
}
#Once this loop terminates all threads are done
for my $thread (@threads) {
my @container;
@container = $thread->join;
print $container[1];
}
线程运行在不同的解释器中,不共享数据,除非变量明确标记为共享。您可以从线程返回值,并在'$ thread-> join'处收集它们。 – amon
嗨,感谢您的评论。我做了你所说的,但它也不起作用。 –