解析嵌套JSON阵列使用GSON

数组我需要使用GSON解析用下列JSON解析嵌套JSON阵列使用GSON

[ 
    "foo", 
    [ 
     "foot mercato", 
     "football", 
     "foot center", 
     "foorzik", 
     "footao" 
    ] 
]

在Java。

林价值观真正感兴趣的阵列：到目前为止，我曾尝试：

String jsonStr = "[" + "\"foo\"," + " [" + " \"foot mercato\"," + " \"football\"," + " \"foot center\"," + 
       " \"foorzik\"," + " \"footao\"" + " ]" + "]"; 

JsonParser parser = new JsonParser(); 
JsonArray array = parser.parse(jsonStr).getAsJsonArray();

什么建议吗？

来源

2014-12-19 RayOldProf

一旦你得到你的数组，你可以迭代它的所有元素。

for(JsonElement e : array) { 
    System.out.println(e); 
}

将输出

"foo" 
["foot mercato","football","foot center","foorzik","footao"]

如果只想嵌套数组中的值，你可以这样做：

JsonArray nestedArray = parser.parse(jsonStr).getAsJsonArray().get(1).getAsJsonArray(); 
for(JsonElement e : nestedArray) { 
    System.out.println(e); 
}

将输出

"foot mercato" 
"football" 
"foot center" 
"foorzik" 
"footao"

来源

2014-12-19 11:27:00

这可能会有所帮助：

String jsonStr = "[" + "\"foo\"," + " [" + " \"foot mercato\"," + " \"football\"," + " \"foot center\"," 
       + " \"foorzik\"," + " \"footao\"" + " ]" + "]"; 

     Gson gson = new Gson(); 
     ArrayList<Object> dest = new ArrayList<Object>(); 
     dest = gson.fromJson(jsonStr, dest.getClass()); 

     for (Object e : dest) { 
      System.out.println("T:" + e.getClass().getCanonicalName()); 
      if (e instanceof String) { 
       System.out.println(e); 
      } else if (e instanceof ArrayList) { 
       for (String ele : (ArrayList<String>) e) { 
        System.out.println(ele); 
       } 
      } 
     }

会生成：

T：java.lang.String中

富

T：java.util.ArrayList中

脚的Mercato

足球

脚中心

foorzik

footao

来源

2014-12-19 11:39:34

解析嵌套JSON阵列使用GSON

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