Bash脚本如果elif elif不工作

Question

所以我想在bash脚本中做一个if else else if语句。截至目前，当我运行此脚本时，出现以下错误消息：“./groupJobs.sh：line 76：语法错误附近出现了令牌elif' ./groupJobs.sh: line 76: elif [$ jobsize -lt $ 2];然后''

我已经在线在多个例子中，在我所做的和别人说的作品中看不到任何区别。

任何帮助，将不胜感激。 （线76是最后的elif语句）

if [ $filesize -ge $2 ]; then 
#goes this way if file is to big to put in a job with anyother files 
$filename >> $jobname$jobnumber; 

elif [ $jobsize -ge $2 ]; then 
#job is done being created 

elif [ $jobsize -lt $2 ]; then 
#add file to job and move on to next file check 

fi 

Answer 1

的elif语句需要一个实际的声明。把下面的这些语句（或者其他任何你想要的）暂时echo "job creation done"和echo "add file to job" ...

if [ $filesize -ge $2 ]; then 
#goes this way if file is to big to put in a job with anyother files 
$filename >> $jobname$jobnumber; 

elif [ $jobsize -ge $2 ]; then 
#job is done being created 
echo "whatever you want" 
#the above line just has to be some sort of actual statement 

elif [ $jobsize -lt $2 ]; then 
#add file to job and move on to next file check 
echo "whatever you want" 
#the above line just has to be some sort of actual statement 
fi 

Answer 2

猛砸在if/elif的块需要一个命令（例如echo）。评论不算。

Answer 3

elif块的主体不能为空（注释不计算在内）。如果您只需要剔除身体，请使用:功能。

if [ $filesize -ge $2 ]; then 
#goes this way if file is to big to put in a job with anyother files 
$filename >> $jobname$jobnumber; 

elif [ $jobsize -ge $2 ]; then 
#job is done being created 
: 

elif [ $jobsize -lt $2 ]; then 
#add file to job and move on to next file check 
: 

fi