如何格式化PSObject的输出？

Question

我有几个网站，每个网站都托管在自己的虚拟机上。我正在制作一份“活文件”，该文件将通过每个网站的某些信息更新CSV文件。

我已经编译了每个元素，并且获取了我想要的信息。但是，导出时我的对象在CSV文件中显示的并不是我想要的。

我得到System.Object[]为$module财产，然后我得到@{property1=value1; property2=value2}为$siteversion。我尝试过使用一些不同的方法来改变这些结果，但我没有看到任何改变。

$scriptBlock = [scriptblock]::Create({  
Import-Module WebAdministration 

###Getting Client Name### 
$licensePath = 'D:\websites\website_Prod\website\license.xml' 
$license = (Get-Content $licensePath) -as [XML] 
$license = $license.software_License 
$license = $license.License 
$clientName = $license.Name  

###Getting Local Path### 
$localPath = Get-WebApplication website | Select -ExpandProperty PhysicalPath  

###Getting the URL### 
$URL = Get-ChildItem -path IIS:SSLBindings | Where-Object {$_.Sites -eq "website"} 
$URL = $URL.Host 

###Getting Security Model### 
$webConfigFilePath = 'D:\websites\website_Prod\website\web.config' 
$webConfigFile = (Get-Content $webConfigFilePath) -as [XML] 
$appSettings = $webConfigFile.configuration.appsettings 
$appSettings = $appSettings.add 
$securityModel = $appSettings | Where-Object {$_.Key -eq "AuthenMode"} | Select-Object -ExpandProperty Value 

###Getting Service Types###  
$licensePath = 'D:\websites\website_Prod\website\license.xml' 
$license = (Get-Content $licensePath) -as [xml] 
$license = $license.software_License 
$license = $license.License 
$module = $license.Module 
$module = $module | Select -ExpandProperty ModuleName   

###Getting Certificate Expiration### 
$sslBinding = Get-ChildItem -Path IIS:SSLBindings 
$cert = $sslBinding | ForEach-Object -Process {Get-ChildItem -path Cert:\localMachine\My | Where-Object -Property Thumbprint -eq -Value $_.Thumbprint} 
$expiration = $cert.NotAfter  

###Getting Site Name### 
$siteNames = Get-ChildItem -Path D:\Websites | Where-Object {$_.Name -notlike "SFTP" -and $_.Name -notlike "wwwroot"} | Select-Object Name 

###Getting Site Versions### 
$siteVersions = @()  
    Foreach($site in $siteNames){ 
     $app = Get-ChildItem d:\websites | Where-Object {$_.Name -eq $site.Name} 
     $app = $app.FullName 
     $app = $app + '\website\bin'   
     $dll = Get-ChildItem $app | Where-Object {$_.Name -eq "website.Core.DLL"} 
     $version = $dll.VersionInfo | Select-Object -ExpandProperty FileVersion 
     $version 
     $versionObject = New-Object -TypeName PSObject 
     $versionObject | Add-Member -MemberType NoteProperty -Name SiteName -Value $Site.Name 
     $versionObject | Add-Member -MemberType NoteProperty -Name Version -Value $version 
     $siteVersions += $versionObject   

    }#Foreach($site in $siteNames) 

$siteInfo = New-Object -TypeName PSObject 
$siteInfo | Add-Member -MemberType NoteProperty -Name ClientName -Value $clientName  
$siteInfo | Add-Member -MemberType NoteProperty -Name Site -Value $siteVersion  
$siteInfo | Add-Member -MemberType NoteProperty -Name ServiceTypes -Value $module 
$siteInfo | Add-Member -MemberType NoteProperty -Name URL -Value $URL 
$siteInfo | Add-Member -MemberType NoteProperty -Name LocalPath -Value $localPath 
$siteInfo | Add-Member -MemberType NoteProperty -Name SecurityModel -Value $securityModel 
$siteInfo | Add-Member -MemberType NoteProperty -Name SSLCertExperiation -Value $expiration 

$siteInfo | export-csv d:\tmp\test.csv -notypeinformation 
})#ScriptBlock 
$data = Invoke-Command -ComputerName server -ScriptBlock $scriptBlock 

Answer 1

基本上，这种情况发生的原因是因为变量不包含您认为它们包含的内容。在调试这些类型的问题时，我通常使用控制台和Get-Member或.GetType()很多。

如果您的代码更易于阅读，这样会更容易。我使用了一种更简单的方式来创建自定义psobject，并且使用了一个GetType()的示例。一旦找出哪些值是对象/散列表而不是简单的字符串/整数，这应该很容易解决。否则，如果他们继续给你带来麻烦，请对具体变量进行评论。

#$siteVersions = @() you can cast $siteVersions as an array on the same line you use it and do not need this line. 
    Foreach($site in $siteNames){ 
     $app = Get-ChildItem d:\websites | Where-Object {$_.Name -eq $site.Name} 
     $app = $app.FullName 
     $app = $app + '\website\bin'   

     $dll = Get-ChildItem $app | Where-Object {$_.Name -eq "website.Core.DLL"} 

     $version = $dll.VersionInfo | Select-Object -ExpandProperty FileVersion 

     # Ensure these are what you expect (i.e.strings) 
     $($site.name).GetType() 
     $version.GetType() 

     # an easy way to create an array of objects 
     [array]$siteVersions += New-Object psobject -Property @{ 
      SiteName = $site.Name 
      Version = $version 
     } 


    }#Foreach($site in $siteNames) 

，简化了第二个对象，以Select-Object用于订购出口：

$siteInfo = New-Object -TypeName PSObject =Property @{ 
    ClientName   = $clientName  
    Site    = $siteVersion  
    ServiceTypes  = $module 
    URL     = $URL 
    LocalPath   = $localPath 
    SecurityModel  = $securityModel 
    SSLCertExperiation = $expiration 
} 

# use Select so that you can see what each column contains. 
$siteInfo | Select-Object ClientName, Site, ServiceTypes, URL, LocalPath, SecurityModel, SSLCertExperiation | export-csv d:\tmp\test.csv -notypeinformation