我从SQLite数据库填充listview,并且当我点击一个项目时应用程序崩溃。我用“查询”和“原始查询”做了足够的研究。在SQLite数据库浏览器中也成功执行了rawquery语句,但仍然是相同的语句在我的代码中不起作用。SQLite查询执行崩溃Android应用程序
下面是我的ListView onitemclicklistener的代码:
// Bookmark ListView Listener
bookmarkListView.setOnItemClickListener(new OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent1, View view1, int position1,
long id1) {
String selectedBookmarkItem = ((TextView)view1).getText().toString();
dbAdapter.read();
Map<String, Object> bookmarkKV = dbAdapter.getSingleBookmark(selectedBookmarkItem);
String bookmarkedURL = (String) bookmarkKV.get(dbAdapter.BOOKMARK_ADDRESS);
dbAdapter.close();
Toast.makeText(getBaseContext(), bookmarkedURL, Toast.LENGTH_LONG).show();
}
});
方法getSingleBookmark代码:
// Fetch Single Bookmark
public Map<String, Object> getSingleBookmark(String bookmarkName1) throws SQLException{
Map<String, Object> map1 = new HashMap<String, Object>();
Cursor cursor1 = db.query(true, BOOKMARKS_TABLE, new String[] {BOOKMARK_ADDRESS},
BOOKMARK_NAME + "=" + bookmarkName1, null, null, null, null, null);
if(cursor1 != null){
cursor1.moveToFirst();
}
String bookmarkAddress = cursor1.getString(cursor1.getColumnIndex(BOOKMARK_ADDRESS));
map1.put(BOOKMARK_ADDRESS, bookmarkAddress);
//String bookmarkName = cursor1.getString(cursor1.getColumnIndex(BOOKMARK_NAME));
//map1.put(BOOKMARK_NAME, bookmarkName);
return map1;
}
logcat的条目:
09-30 03:43:12.791: E/AndroidRuntime(29008): FATAL EXCEPTION: main
09-30 03:43:12.791: E/AndroidRuntime(29008): android.database.sqlite.SQLiteException:
no such column: gmail (code 1): , while compiling: SELECT DISTINCT bookmarkaddress
FROM bookmarkstable WHERE bookmarkname=gmail
当我点击在 “Gmail的” 项目listview,该应用程序崩溃说:“不幸的是,应用程序已停止”。
但数据库表中有一行“Gmail的”条目:
看看这个查询,它看起来像Gmail应该有单引号,例如, 'SELECT DISTINCT bookmarkaddress FROM bookmarkstable WHERE bookmarkname ='gmail'' –
每当有东西崩溃,就会产生一个异常。您可以将这些数据写入日志文件并查看:) –
您可以发布您的数据库类的onCreate方法代码吗? –