编码字符串的http get/post

Question

我有关于发送和获取图像的编码数据的问题。首先我有图像作为字符串Base64编码类型，这串具有一个值，如以下： ... d/2wBDAA0JCgsKCA0LCgsODg0PEyAVExISEyccHhcgLikxMC4pLSwzOko + MZZ ...

，如果我现在再次进行解码，并且如果我使用BitmapFactory以适应在imageview这就是所有正确的形象是好的。

byte[] bytes= stream.toByteArray();        
imagestr=Base64.encodeBytes(bytes).toString(); 
//If i code below it is working 
byte[] decode = Base64.decode(imagestr); 
decoded = BitmapFactory.decodeByteArray(decode, 0, decode.length); 

//If i send to the server and handle it in servlet file 
String pic = request.getParameter("p"); 
byte[] servdec = Base64.decode(pic); 
//and if i use the servdec to output a image file file is corrupted. 
//I noticed the pic and imagestr are different 
//imagestr = **...D/2wBDAA0JCgsKCA0LCgsODg0PEyAVExISEyccHhcgLikxMC4pLSwzOko+MzZ...** 
//pic  = **...D/2wBDAA0JCgsKCA0LCgsODg0PEyAVExISEyccHhcgLikxMC4pLSwzOko MzZ...** 
//pic has no + sign. 

我使用了replaceAll，但仅限于这种情况。它可能会导致更多的问题。那么有没有可以咨询感谢你的答案...

嗨任何解决方案，这个字符串在谈到这个功能，这个功能servlet将处理这个后PIC！石化公司+登录该功能
公共字符串uuidfaceid（UUID字符串，字符串faceid，字符串名称，字符串PIC）{

URL url = null; 

try { 

url = new 

URL（ “HTTP：//” + Constants.SERVER_NAME + Constants.SERVER_PORT + “/ MeetInTouch/UF” +“ ？ uuid =“+ uuid +”& faceid =“+ faceid +”& name =“+ name +”& pic =“+ pic）;

} catch (MalformedURLException e1) { 

e1.printStackTrace(); 

} 

URLConnection ucon = null; 

try { 

ucon = url.openConnection(); 

} catch (IOException e1) { 

e1.printStackTrace(); 

} 

try { 

ucon.connect(); 

} catch (IOException e1) { 

e1.printStackTrace(); 

} 

Answer 1

包含Base64编码字符串的“p”参数在某个点已被“url解码”。所有你需要做的就是再次对其进行编码，尝试前向Base64编码解码：

String pic = request.getParameter("p"); 
pic = URLEncoder.encode(pic, "ISO-8859-1"); 
byte[] servdec = Base64.decode(pic);