为Oracle中的每个重复值自动递增

Question

我正在使用Oracle数据库集成器（ODI）为新表创建接口。

我想要做的是逐渐增加一个数字，为​​每个重复出现的另一列中的值。例如，对于表：

Person_ID | ... 
32   | ... 
45   | ... 
32   | ... 
67   | ... 
45   | ... 
45   | ... 

接口将在目标表输出如下：

Person_ID | Sequence_Number | ... 
32  |  1   | ... 
45  |  1   | ... 
32  |  2   | ... 
67  |  1   | ... 
45  |  2   | ... 
45  |  3   | ... 

我试图通过进入不同的SQL查询到在实现文本编辑器来做到这一点映射属性，但似乎我实际上无法使其逐渐增加。

任何帮助将不胜感激！

Answer 1

可以使用row_number()，或rank()与over(partition by personId order by personId)

select personId, 
     row_number() over(partition by personId order by personId) Sequence_Number 
from your_table 

编辑：如果要排序的正是像你提到的期望的输出结果，你需要做的order by rownum两次，以保证所需的排序：

select personId, 
     row_number() over(partition by personId order by rownum) Sequence_Number 
from your_table 
order by rownum 

下面是上面查询检查：

---

SQL> create table your_table (personId int); 

Table created. 

SQL> insert all 
    2  into your_table values(32) 
    3  into your_table values(45) 
    4  into your_table values(32) 
    5  into your_table values(67) 
    6  into your_table values(45) 
    7  into your_table values(45) 
    8  select * from dual; 

6 rows created. 

SQL> commit; 

Commit complete. 

SQL> select personId, 
    2   row_number() over(partition by personId order by rownum) Sequence_Number 
    3 from your_table; 

    PERSONID SEQUENCE_NUMBER 
---------- --------------- 
     32    1 
     32    2 
     45    1 
     45    2 
     45    3 
     67    1 

6 rows selected. 

SQL> select personId, 
    2   row_number() over(partition by personId order by rownum) Sequence_Number 
    3 from your_table 
    4 order by rownum; 

    PERSONID SEQUENCE_NUMBER 
---------- --------------- 
     32    1 
     45    1 
     32    2 
     67    1 
     45    2 
     45    3 

6 rows selected. 

SQL> drop table your_table; 

Table dropped. 

SQL>