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我想将登录用户存储在新的会话中,从数据库获取信息,将其放入json数组,然后在android中获取数组在布局中显示结果。但是,当我运行应用程序时,从php文件返回的数组是空的。如果我在不同的程序,如邮差但是测试php文件,我得到正确的响应
{"result":[{"id":"12","fname":"C","lname":"Wei","username":"cw","email":"werrs.com"}]}
这里是php文件和Java方法。
<?php
session_start();
if($_SERVER['REQUEST_METHOD'] == 'GET'){
$username = $_SESSION['username'];
$sql = "SELECT * FROM USER WHERE username = '$username'";
require_once('connect.inc.php');
$run = mysqli_query($conn, $sql);
$result = array();
while($row = mysqli_fetch_array($run)){
array_push($result, array(
'id' => $row['id'],
'fname' => $row['fname'],
'lname' => $row['lname'],
'username' => $row['username'],
'email' => $row['email'],
));
}
echo json_encode(array('result'=>$result));
mysqli_close($conn);
}
?>
在邮差,它成功地获取登录的用户,但在Android它不。
private void getUserData() { StringRequest stringRequest = new
StringRequest(Request.Method.GET,
Config.SERVER_ADDRESS + "GetUserData.php",
new Response.Listener<String>() {
@Override
public void onResponse(String response) {
JSONObject jsonObject = null;
try {
//json string to jsonobject
jsonObject = new JSONObject(response);
//get json sstring created in php and store to JSON Array
result = jsonObject.getJSONArray(Config.json_array);
//get username from json array
getUserInfo(result);
} catch (JSONException e) {
e.printStackTrace();
}
}
},
new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
}
});
RequestQueue requestQueue = Volley.newRequestQueue(this);
requestQueue.add(stringRequest);
}
private void getUserInfo(JSONArray jsonArray){
for(int i = 0; i < jsonArray.length(); i++) {
try {
JSONObject json = jsonArray.getJSONObject(i);
userInfo.add(json.getString(Config.getUsername));
} catch (JSONException e) {
}
}
}
我使用散列表来做这个吗? – cdub
只需以最适合您的需求的格式存储以前获取的会话标识并将其附加到以下请求:Config.SERVER_ADDRESS +“GetUserData.php?PHPSESSID =”+ myPreviouslyStoredSessionId –
好的。我正在努力获取会话ID。 – cdub