开关的阵列的子阵列的第一个元素

ARRAY 1：

Array (
    [0] => Array (
    [fStartValidTime] => 2012-03-13 
    [fMaxTemp] => 7 
    [fMinTemp] => 2 
) 
    [1] => Array (
    [fStartValidTime] => 2012-03-14 
    [fMaxTemp] => 7 
    [fMinTemp] => 5 
) 
    [2] => Array (
    [fStartValidTime] => 2012-03-15 
    [fMaxTemp] => 10 
    [fMinTemp] => 5 
) 
    [3] => Array (
    [fStartValidTime] => 2012-03-16 
    [fMaxTemp] => 10 
    [fMinTemp] => 1 
) 
    [4] => Array (
    [fStartValidTime] => 2012-03-17 
    [fMaxTemp] => 7 
    [fMinTemp] => 3 
) 
    [5] => Array (
    [fStartValidTime] => 2012-03-18 
    [fMaxTemp] => 7 
    [fMinTemp] => 3 
) 
    [6] => Array (
    [fStartValidTime] => 2012-03-19 
    [fMaxTemp] => 7 
    [fMinTemp] => 1 
) 
)

ARRAY 2：

Array (
    [2] => Array (
    [fStartValidTime] => 2012-03-13T16:00:00-7:00 
    [fMaxTemp] => 6 
    [fMinTemp] => 6 
    [fWeatherType] => chancerain 
    [fProbability] => likely 
    [fCloudCoverPercent] => 20 
) 
    [5] => Array (
    [fStartValidTime] => 2012-03-13T19:00:00-7:00 
    [fMaxTemp] => 6 
    [fMinTemp] => 6 
    [fWeatherType] => chancerain 
    [fProbability] => likely 
    [fCloudCoverPercent] => 20 
) 
    [8] => Array (
    [fStartValidTime] => 2012-03-13T22:00:00-7:00 
    [fMaxTemp] => 5 
    [fMinTemp] => 5 
    [fWeatherType] => chancerain 
    [fProbability] => likely 
    [fCloudCoverPercent] => 20 
) 
)

我想切换的Array2的fMaxtTemp AMD fMinTemp仅为Array2的第一个元素的Array1。所以

[2] => Array (
    [fStartValidTime] => 2012-03-13T16:00:00-7:00 
    [fMaxTemp] => 6 
    [fMinTemp] => 6 
    [fWeatherType] => chancerain 
    [fProbability] => likely 
    [fCloudCoverPercent] => 20 
)

将成为

[2] => Array (
    [fStartValidTime] => 2012-03-13T16:00:00-7:00 
    [fMaxTemp] => 7 
    [fMinTemp] => 2 
    [fWeatherType] => chancerain 
    [fProbability] => likely 
    [fCloudCoverPercent] => 20 
)

来源

2012-03-13 Autolycus

这里有一个简单的解决方案：

新版本响应DaveRandom的评论：

<?php 
$tmp = array_keys($array2); 
$array2_first_idx = $tmp[0]; 
if (count($array1) > 0 && count($array2) > 0) { // Prevent PHP Notice for empty arrays 
    $array2[$array2_first_idx]['fMaxTemp'] = $array1[0]['fMaxTemp']; 
    $array2[$array2_first_idx]['fMinTemp'] = $array1[0]['fMinTemp']; 
}

原始版本：

<?php 
if (count($array1) > 0 && count($array2) > 0) { // Prevent PHP Notice for empty arrays 
    $array2['0']['fMaxTemp'] = $array1['0']['fMaxTemp']; 
    $array2['0']['fMinTemp'] = $array1['0']['fMinTemp']; 
}

或者，如果你想获得幻想，并在尽可能多的阵列位置取代尽可能多的按键，只要你想：

<?php 
public function swap_array_values($a1, $a2, $pos, $keys) 
{ 
    $tmp = $a2; 

    foreach ($pos AS $idx) { 
     // Make sure we have a value in the position we want to swap 
     if (array_key_exists($idx, $a1) && array_key_exists($idx, $a2)) { 
      foreach ($keys AS $key) { 
       if (array_key_exists($key, $a1[$idx]) && array_key_exists($key, $a2[$idx])) { 
        $tmp[$idx][$key] = $a1[$idx][$key]; 
       } 
      } 
     } 
    } 

    return $tmp; 
} 

// ------------------------------------------------------------------- 

$positions = array('0'); 
$swap_keys = array('fMaxTemp', 'fMinTemp'); 

echo "Before:<br/>"; 
echo "<strong>Array 1</strong><pre>"; print_r($array1); echo "</pre>"; 
echo "<strong>Array 2</strong><pre>"; print_r($array2); echo "</pre>"; 

$array2 = swap_array_values($array1, $array2, $positions, $swap_keys); 

echo "<hr/>After:<br/>"; 
echo "<strong>Array 2</strong><pre>"; print_r($array2); echo "</pre>";

来源

2012-03-13 21:02:38 augustknight

替换'[0]'和' ''这会做！ – Basti 2012-03-13 21:10:37

不可以，因为数组2的索引是'2'。这就是为什么我的答案使用方法使第一个元素的关键是无关紧要的原因。我怀疑的是整个观点，因为一个简单的任务在这里很少引发一个问题...... – DaveRandom 2012-03-13 21:15:20

// Make sure the array pointers are at the beginning 
reset($arr1); 
reset($arr2); 

// Get the the key of the first element from each array 
$k1 = key($arr1); 
$k2 = key($arr2); 

// Update the values in $arr1 with those from $arr2 
$arr2[$k2]['fMaxtTemp'] = $arr1[$k1]['fMaxtTemp']; 
$arr2[$k2]['fMintTemp'] = $arr1[$k1]['fMintTemp'];

来源

2012-03-13 21:10:13 DaveRandom

开关的阵列的子阵列的第一个元素

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