javascript检查结束日期是否大于或等于开始日期

Question

是否有可能检查结束日期是否大于或等于Javascript中的开始日期？我的日期是'dd/mm/yyyy'格式的字符串。

Answer 1

试试这个

var startDate = "05/01/2011"; 
var endDate = "09/01/2011"; 
var regExp = /(\d{1,2})\/(\d{1,2})\/(\d{2,4})/; 
if(parseInt(endDate.replace(regExp, "$3$2$1")) > parseInt(startDate.replace(regExp, "$3$2$1"))){ 
alert("greater"); 
} 

Answer 2

退房此功能

function CompareDates() 
{ 
var str1 = document.getElementById("Fromdate").value; 
var str2 = document.getElementById("Todate").value; 
var dt1 = parseInt(str1.substring(0,2),10); 
var mon1 = parseInt(str1.substring(3,5),10); 
var yr1 = parseInt(str1.substring(6,10),10); 
var dt2 = parseInt(str2.substring(0,2),10); 
var mon2 = parseInt(str2.substring(3,5),10); 
var yr2 = parseInt(str2.substring(6,10),10); 
var date1 = new Date(yr1, mon1, dt1); 
var date2 = new Date(yr2, mon2, dt2); 

if(date2 < date1) 
{ 
    alert("To date cannot be greater than from date"); 
    return false; 
} 
else 
{ 
    alert("Submitting ..."); 
    document.form1.submit(); 
} 
} 

Answer 3

如果字符串格式（ 'DD/MM/YYYY'）不会改变，这个功能应该工作：

function endAfterStart(start,end){ 
    return new Date(start.split('/').reverse().join('/')) < 
      new Date(end.split('/').reverse().join('/')); 
} 
alert(endAfterStart('05/01/2011','09/01/2011')); //=> true 

或延长Date.prototype：

Date.prototype.isBefore = Date.prototype.isBefore || function(dat){ 
    return this < dat; 
} 
new Date('05/01/2011'.split('/').reverse().join('/')) 
    .before(new Date('09/01/2011'.split('/').reverse().join('/'))); //=>true 

Answer 4

花了我一些时间来寻找，但JQuery实现了这个确切的功能与DatePickerdate-range。 （源代码也可以在链接中找到。）

Moment.js也使用diff函数很好地处理日期比较。

Answer 5

试试这个，

function isDateCompare(){ 

var leadDate = document.getElementById('strDate').value; 

var closeDate = document.getElementById('strDateClosed').value; 

var date1 = new Date(); 

date1.setFullYear(leadDate.substr(6,4),(leadDate.substr(3,2)-1),leadDate.substr(0,2)); 

var date2 = new Date(); 

date2.setFullYear(closeDate.substr(6,4),(closeDate.substr(3,2)-1),closeDate.substr(0,2)); 

if (date1> date2) 
{ 

alert("Expected Closed date cannot be less than Lead date."); 

return false; 

} 

else 
{ 

alert("true"); 

return false; 

} 

} 

Answer 6

function isDate(value) 
      { 
       var fromDate = document.getElementById("fromDate").value 
       var toDate= document.getElementById("toDate").value 
       //var curr_Date= new SimpleDateFormat("dd/mm/yyyy"); 


      var dateRegEx = null; 
      dateRegEx = new RegExp(/^(((0[1-9]|[12]\d|3[01])\/(0[13578]|1[02])\/((19|[2-9]\d)\d{2}))|((0[1-9]|[12]\d|30)\/(0[13456789]|1[012])\/((19|[2-9]\d)\d{2}))|((0[1-9]|1\d|2[0-8])\/02\/((19|[2-9]\d)\d{2}))|(29\/02\/((1[6-9]|[2-9]\d)(0[48]|[2468][048]|[13579][26])|((16|[2468][048]|[3579][26])00))))$/g); 

      if (dateRegEx.test(fromDate)){ 
      } 
      else{ 
       alert("Invalid from date"); 
       return false; 
      } 
      dateRegEx = new RegExp(/^(((0[1-9]|[12]\d|3[01])\/(0[13578]|1[02])\/((19|[2-9]\d)\d{2}))|((0[1-9]|[12]\d|30)\/(0[13456789]|1[012])\/((19|[2-9]\d)\d{2}))|((0[1-9]|1\d|2[0-8])\/02\/((19|[2-9]\d)\d{2}))|(29\/02\/((1[6-9]|[2-9]\d)(0[48]|[2468][048]|[13579][26])|((16|[2468][048]|[3579][26])00))))$/g); 
      if(dateRegEx.test(toDate)) { 
      } 
      else{ 
       alert("Invalid to date"); 
       return false; 
      } 
      var stDate = new Date(fromDate); 
      var enDate = new Date(toDate); 
      var compDate = enDate - stDate; 
      //var fdate=enDate-curr_Date; 

      if(compDate >= 0) 
       return true; 
      else 
      { 
       alert("To Date cannot be smaller than From Date"); 
       return false; 
      } 




      /**/ 
     } 

这将为闰年also..in DD/MM/YYYY格式（没有任何其他格式）工作。

Answer 7

第一次使用此功能将字符串转换为Date类型在JS：

function common_getDateFromUI(str) { 
    var arr = str.split("/"); 
    var returnDate = new Date(arr[2], arr[1] - 1, arr[0], 0, 0, 0, 0); 
    return returnDate; 
} 

二：你的JavaScript日期类型后，你只需把它比正常型像日期1> date2的或DATE1 == DATE2 。
或者使用该功能来获取日期之间的区别日期：

function CalendarDays(startDate, endDate) { 
    if (endDate < startDate) 
     return 0; 

    // Calculate days between dates 
    var millisecondsPerDay = 86400 * 1000; // Day in milliseconds 
    startDate.setHours(0, 0, 0, 1); // Start just after midnight 
    endDate.setHours(23, 59, 59, 999); // End just before midnight 
    var diff = endDate - startDate; // Milliseconds between datetime objects 
    var days = Math.round(diff/millisecondsPerDay); 

    return days; 
} 

请点击此链接是一个简单的演示，以获得日期之间的差异天。 Link demo here

Answer 8

if (iForm.DiddfromDate.value == "") 
    { 
    alert(" Please enter a value"); 
    iForm.DiddfromDate.focus(); 
    return false;  
    } 
    if (iForm.DiddtoDate.value == "") 
    { 
    alert(" Please enter a value"); 
    iForm.DiddtoDate.focus(); 
    return false;  
    }  
     try { 
      var d1 = iForm.DiddfromDate.value.substr(0, 2); 
      var m1 = iForm.DiddfromDate.value.substr(3, 2); 
      var y1 = iForm.DiddfromDate.value.substr(6, 4); 
      var StrDate = m1 + "/" + d1 + "/" + y1; 

      var d2 = iForm.DiddtoDate.value.substr(0, 2); 
      var m2 = iForm.DiddtoDate.value.substr(3, 2); 
      var y2 = iForm.DiddtoDate.value.substr(6, 4); 
      var EndDate = m2 + "/" + d2 + "/" + y2; 

      var startDate = new Date(StrDate); 
      var endDate = new Date(EndDate); 
      if (startDate > endDate) { 
       alert('To date should be greater than From date.'); 
       iForm.DiddfromDate.value = ''; 
       iForm.DiddtoDate.value = ''; 
       iForm.DiddfromDate.focus(); 
       return false; 
      } 
     } catch (e) { alert(e.Description); } 
return true; 

Answer 9

最简单的方法来做到这一点。

function endAfterStart(start, end) { 
    var startDate = new Date(start); 
    var endDate = new Date(end); 

    return endDate.getTime() >= startDate.getTime(); 
} 

Answer 10

只需将字符串转换为日期并使用Date对象的getTime方法进行比较即可。

示例代码

var startDate = '04/04/2015'; //date in dd/mm/yyyy format 
var endDate = '05/04/2015'; 

function compareDates(sDate, eDate) { 
    var dateTime1 = new Date(sDate).getTime(), 
     dateTime2 = new Date(eDate).getTime(); 
    var diff = dateTime2 - dateTime1; 
    if (diff > 0) { 
    alert("endDate is greater than startDate"); 
    return true; 
    } 
} 
compareDates(startDate, endDate); 

Working Fiddle