在php中用mysql跳过空记录

我想做一个调查，但是当我在我的msql数据库中有一个空记录时，他只是显示一个空的问题，是否有可能跳过空记录？在php中用mysql跳过空记录

<?php 
session_start(); 

include "config.php"; 
connDB(); 


$some_questions = mysql_num_rows(mysql_query("SELECT id FROM question"));   

if($_POST['next'] && $_SESSION['qnumber'] != '' && $_POST['question'.$_SESSION['qnumber']] != '') 
{ 
    if($_POST['question1']){ 
     $_SESSION['antwoordjes'] = $_POST['question1']; 
    }else{ 
     $_SESSION['antwoordjes'] .= '|'.$_POST['question'.$_SESSION['qnumber']]; 
    } 
    $_SESSION['qnumber']++; 
    $questionnumber = $_SESSION['qnumber']++; 
    $sql = "SELECT id, question FROM question WHERE id = '$questionnumber'"; 
    $result = mysql_query($sql); 
    while ($count = mysql_fetch_array($result)){ 

     if($count['question'] == null) 
     { 
      $_SESSION['qnumber']++; 
     } 
    } 

} 

if($_POST['question'.$some_questions] != '' && $_SESSION['qnumber'] >= ($some_questions + 1)) 
{ 
    mysql_query("INSERT INTO answers (ip,answers,datum) VALUES ('".$_SERVER['REMOTE_ADDR']."','".$_SESSION['antwoordjes']."',NOW())"); 
    session_destroy(); 
    header("Location: outro.php"); 
} 

if($_SESSION['qnumber'] == '' || $_SESSION['qnumber'] >= ($some_questions + 1)) 
{ 
    $quest = 1; 
    $_SESSION['qnumber'] = $quest; 
} 
else{ 
    $quest = $_SESSION['qnumber']; 
} 

$data = mysql_fetch_array(mysql_query("SELECT question,answers FROM question WHERE id='".$quest."'")); 


$answers = explode('|',$data['answers']); 

$quest = stripslashes($data['question']); 

if(empty($_POST['atext'])) 
{ 

}else{ 

    $quest = $_POST['hsvraag']; 
    $commentary = $_POST['atext']; 
    toevoegenOverig($commentary, $quest); 
} 

?> 
<script type="text/javascript"> 
function disablefield(){ 
if (document.getElementById('yes_radio').checked == 1){ 
document.getElementById('textbox_A').disabled='disabled'; 
document.getElementById('textbox_A').value=''; 
}else{ 
document.getElementById('textbox_A').disabled=''; 
document.getElementById('textbox_A').value=''; } 
} 
</script> 
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> 
<html xmlns="http://www.w3.org/1999/xhtml"> 
<head> 
<!-- <script type="text/javascript" src="abc.js"></script> --> 
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1" /> 
<title>Internet onderzoek</title> 
<link href="style.css" rel="stylesheet" type="text/css" /> 
</head> 

<body> 
<table align="left"> 
</table> 
<div class="centrum"> 
<div class="header">Internetsurvey</div> 
<div class="content" id="content"> 
<div class="balk">Introductie | <span style="color:#000033;">question</span> | end</div> 
<br/> 
<form method="post" action="vragenv.php"> 
<?php 
$nummer = 1; 
foreach($answers as $answer) 
{ 
    echo '<input id="yes_radio" type="radio" name="question'.$_SESSION['qnumber'].'" value="'.$nummer.'" id="answer'.$nummer.'" onChange="disablefield();"/><label for="answer'.$nummer.'">'.$answer.'</label><br />'; 
    echo '<input type="hidden" name="hsvraag" value="'.$quest.'"/>'; 
    $nummer++; 
} 
?> 
</br> 
<br/><input type="text" id="textbox_A" required name="atext"/><br /> 
<input type="submit" name="next" value="next" class="knop" /> 
</form> 
</div> 
</div> 
</body> 
</html>

来源

2012-02-07 user1194634

试'$数据= mysql_fetch_array（的mysql_query（ “SELECT问题，回答问题FROM WHERE ID = '” $任务。 “' AND问题<> '”'））;' – diEcho 2012-02-07 12:54:35

调整您的查询。

SELECT 
    `id`, 
    `question` 
FROM 
    `question` 
WHERE 
    `id` = '$questionnumber' 
    AND 
    `question` IS NOT NULL 
    AND 
    LENGTH(TRIM(`question`))>1

来源

2012-02-07 12:55:00

在php中用mysql跳过空记录

回答

相关问题