您是否需要显示各个费用行以及所有总计?如果没有,你可以组由supplierinv列,总结的数额:
select supplierinv, sum(amount) as invoice_amount
from expenses group by supplierinv
,那么你可以简单地添加所有INVOICE_AMOUNT值的客户端来获取总计。
,如果你确实需要每个费用行,你可以做发票聚合客户端相当容易:
$invtotals = array();
$grand_total = 0;
foreach (getexpenses() as $row) {
$supplierinv = $row['supplierinv'];
if (!array_key_exists($supplierinv, $invtotals)) {
$invtotals[$supplierinv] = 0;
}
$invtotals[$supplierinv] += $row['amount'];
$grand_total += $row['amount'];
}
另一种方法,如果你想显示表分成发票,是只保证
$grand_total = 0;
$invoice_total = 0;
$current_invoice = -1;
foreach (getexpenses() as $row) {
if ($current_invoice > 0 && $current_invoice != $row['supplierinv']) {
show_invoice_total($current_invoice, $invoice_total);
$grand_total += $invoice_amount;
$current_invoice = $row['supplierinv'];
$invoice_total = 0;
}
$invoice_total += $row['amount'];
show_expense($row);
}
if ($current_invoice > 0) {
show_invoice_total($current_invoice, $invoice_total);
$grand_total += $invoice_amount;
}
show_grand_total($grand_total);
您可以让数据库做聚合每个发票和总计像这样:
select date, supplierinv, amount,
sum(amount) over(partition by supplierinv) as invoice_amount,
sum(amount) over()
from expenses
结果由supplierinv然后命令
虽然你仍然需要做一些后处理来显示这个明智的,所以这并没有真正获得任何imho。