我试图抓住从2桌,一个具有以下结构的结果:具有以下结构MySQL查询问题
CREATE TABLE `users`
(
`id` bigint (20) NOT NULL AUTO_INCREMENT ,
`firstname` varchar (255) NOT NULL,
`lastname` varchar (255) NOT NULL,
`sex` varchar (255) NOT NULL,
`orientation` varchar (50),
`email` varchar (255) NOT NULL,
`altemail` varchar (255),
`username` varchar (255) NOT NULL,
`password` varchar (255) NOT NULL,
`school` varchar (255) NOT NULL,
`age` date NOT NULL,
`image1` varchar (255),
`image2` varchar (255),
`image3` varchar (255),
`image4` varchar (255),
`image5` varchar (255),
`music` longtext,
`movies` longtext,
`tv` longtext,
`books` longtext,
`saysomething` longtext,
`course` varchar (255),
`YEAR` integer (11),
`verified` varchar (255),
`verifieddatetime` datetime,
`string` varchar (255),
`alerts` varchar (50),
PRIMARY KEY (`id`)
)
而且一个:
CREATE TABLE `timetable`
(
`id` bigint (20) NOT NULL AUTO_INCREMENT ,
`studentid` varchar (255),
`classno` varchar (50),
`classname` varchar (255),
`classnumber` varchar (255),
`prof` varchar (255),
PRIMARY KEY (`id`)
)
用户名是存储作为时间表中的外键。每个学生在时间表中输入他们的课程。试图做一个搜索结果,该搜索结果将生成与当前用户在同一所学校的同一班级中的所有人。需要返回users表中的id,firstname,lastname,image1字段以及时间表表的classname,classnumber。我有以下查询来抓取同一学校的用户的结果:
$query = "select users.id, users.firstname, users.lastname, users.age, users.image1, users.school, category.category from users, category where users.image1 !='male.gif' and users.image1 !='female.gif' and users.verified ='yes' and users.username !='$_SESSION[myusername]' and users.school = '$school' and users.school = category.cat_id";
但我不知道如何抓取类。任何帮助将不胜感激。谢谢。