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在下面的代码,我有我已填充带有参数的字典“nissi_params_fields”:包括字典匿名类型,然后序列化,形成JSON
Dictionary<string, string> nissi_params_fields = new Dictionary<string, string>();
string[] separator = { "," };
string[] dfields = form_fields.Split(separator, StringSplitOptions.RemoveEmptyEntries);
string[] ffields = db_fields.Split(separator, StringSplitOptions.RemoveEmptyEntries);
foreach (var field in ffields)
{
NissiMain nm = new NissiMain();
object field_object = nm.nissi_get_object_by_name(field);
string fieldvalue = nm.nissi_get_object_value_by_name(field_object);
nissi_params_fields[field] = fieldvalue;
this.nissiSetStorageItem(save_page, field, fieldvalue);
}
nissi_params_fields["company_id"] = this.nissiGetStorageItem("nissi_base", "ni_companyID");
string nissi_params_id = "";
if (save_type == "edit")
{
nissi_params_fields["id"] = this.nissiGetStorageItem(save_page, "id");
nissi_params_id = this.nissiGetStorageItem(save_page, "id");
}
我现在要创建一个包含匿名类型上述“nissi_params_fields”字典作为一个字段“田”,所以我第一次尝试“nissi_params_fields”转换为对象“nissi_params_fields_object”我可以在Newtonsoft JObject“nissi_params_object”使用:
object nissi_params_fields_object = nissi_params_fields.ToArray();
的挑战是如何转换吨他字典到一个对象...我怎么做到这一点?
我现在想在匿名类型转换后的对象“nissi_params_fields_object”,然后使用序列化整个事情到JSON的Newtonsoft JObject:
JObject nissi_params_object = JObject.FromObject(new
{
apikey = this.nissiGetStorageItem("nissi_base", "ni_apiKey"),
company_id = this.nissiGetStorageItem("nissi_base", "ni_companyID"),
id = nissi_params_id,
fields = nissi_params_fields_object,
});
你为什么要转换字典? –
谢谢pravprab!我只是想以/url.php?nissi_request=MyRequest&nissi_params={"apikey":"xxyyzz","company_id":"1",fields={"lastname":"hello“的格式创建url字符串(带有JSON参数) ”, “名字”: “世界”}} – bolaji