2016-01-22 52 views
0

我正在创建一个测试来填写注册表单的前端,但是,我想单击下拉箭头选择值,然后检查所选值是否为预期值:我可以从下拉列表中选择值并输入值,但是,我所遇到的问题是检查所选值是否正确。代码和错误是如下:从控制台Selenium Web-driver从下拉菜单中选择索引值

driver.findElement(By.cssSelector("#dijit_form_Select_1 > tbody > tr > td.dijitReset.dijitRight.dijitButtonNode.dijitArrowButton.dijitDownArrowButton.dijitArrowButtonContainer > input")).click(); 


     WebElement Menuitem = driver.findElement(By.cssSelector("#dijit_MenuItem_6_text")); 

     boolean click1 = true; 

       Menuitem.click(); 

       //Checks if drop down button is selected 
       click1 = Menuitem.isSelected(); 

       if(click1 == false){ 
        System.out.println("DropDown Was Selected"); 
       }else { 
        System.out.println("DropDown was not clicked"); 
       } 



       Select Menuitem6 = new Select(driver.findElement(By.id("dijit_form_Select_1"))); 

       Menuitem6.selectByVisibleText("Mr"); 

       List<WebElement> list = Menuitem6.getOptions(); 

       for(int i=0;i<list.size();i++){ 
        if(list.get(i).getText().equals(Menuitem6.getFirstSelectedOption().getText())){ 
         System.out.println("The index of the selected option is: "+i); 
         break; 
         } 

错误:org.openqa.selenium.support.ui.UnexpectedTagNameException: Element should have been "select" but was "table"

所以问题是明显,这是因为HTML元素是一个表,而不是一个选择,我该如何解决这个问题得到什么?

HTML代码:

<tr aria-selected="false" widgetid="dijit_MenuItem_6" aria-disabled="false" aria-label="Mr " id="dijit_MenuItem_6" style="-moz-user-select: none;" class="dijitReset dijitMenuItem" data-dojo-attach-point="focusNode" role="option" tabindex="-1"> 
    <td class="dijitReset dijitMenuItemIconCell" role="presentation"> 
     <span role="presentation" class="dijitInline dijitIcon dijitMenuItemIcon dijitNoIcon" data-dojo-attach-point="iconNode"></span> 
    </td> 
    <td id="dijit_MenuItem_6_text" class="dijitReset dijitMenuItemLabel" colspan="2" data-dojo-attach-point="containerNode,textDirNode" role="presentation">Mr</td> 
    <td id="dijit_MenuItem_6_accel" class="dijitReset dijitMenuItemAccelKey" style="display: none" data-dojo-attach-point="accelKeyNode"></td> 
    <td class="dijitReset dijitMenuArrowCell" role="presentation"> 
     <span data-dojo-attach-point="arrowWrapper" style="visibility: hidden"> 
      <span class="dijitInline dijitIcon dijitMenuExpand"></span> 
      <span class="dijitMenuExpandA11y">+</span> 
     </span> 
    </td> 
+0

请发布HTML。 – AlexCharizamhard

+0

这些值不在选择中,这是它不工作的原因。它们在一个表格中,值保存在​​ – Speedychuck

+0

如果这是选择Menuitem6.selectByVisibleText(“Mr”);你想要的价值。将绝对Xpath用于保存值的元素,然后使用GetAttribute()进行评估。 – AlexCharizamhard

回答

0

这似乎是很多工作,为断言选择的值是正确的。

不是遍历所有选项,而是选择并使用GetAttribute(“Selected”)== true时,不只是引用相同的元素。特别是,如果该选择功能正在处理该元素。

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