PHP SQL与多个选择不工作

Call to undefined method mysqli_stmt::get_result() on line 21.

我不明白这是如何工作的对象，为什么我可以做的第一个数据库调用而不是第二。

<?php 

    header('Content-Type: application/json'); 
    include_once 'do_dbConnect.php'; 
    include_once 'functions.php'; 
    sec_session_start(); 

    //identify who took the last call 
    $stmt = $mysqli->stmt_init(); 
    if ($stmt->prepare("SELECT MAX(dateOfCall), id FROM call")) { //setup the query statement 
     $stmt->execute(); //execute the statement 
     $result = $stmt->get_result(); //get the results 
     $row = $result->fetch_assoc(); //get the first row 
     $user_id = $row['id']; //get the id column 
    } 


    //identify how many team members there are 
    if ($stmt->prepare("SELECT id FROM teamMembers")) { //setup the query statement 
     $stmt->execute(); //execute the statement 
     $result = $stmt->get_result(); //get the results 
     $memberCount = $result->num_rows; 
    } 


    //get next user 
    if ($stmt = $mysqli->prepare("SELECT * FROM teamMembers WHERE id = (? + 1) % ?")) { //setup the query statement 
     $stmt->bind_param('ii', $user_id, $memberCount); 
     $stmt->execute(); //execute the statement 
     $result = $stmt->get_result(); //get the results 
     $row = $result->fetch_assoc(); //get the first row 
     $next_user_id = $row['id']; //get the id column 
     $next_user_name = $row['username']; 
    } 
    $stmt->close(); 
    //get the next call taker from the teamMember table 

    echo json_encode($row); 

    ?>

来源

2014-07-25 b1shp

请指定哪些线是21 ??你怎么知道第一个mysqli电话是好的？ –

我不知道你的问题的答案，但我总是发现，理解事情的工作往往是最重要的一步。看到这个评论：http://stackoverflow.com/a/8343970/1888402另外，不要害羞，这是一个公共论坛，人们喜欢得到帮助人们的积分，因此这对所有参与者都是双赢的。 –

一个问题是您的第一个查询**调用**是您需要的[* Mysql保留关键字*]（http://dev.mysql.com/doc/refman/5.6/en/reserved-words.html）用bact-ticks逃脱它 –